The state equations of a second degree circuit are given below. Find the zero-state response of the inductor current iL(t). d [Vc(t) + dt

In the circuit shown the initial voltages across the capacitors C, and C₂ are 2V and 4V, respectively. The switch is closed at time t = 0. The total energy dissi- pated (in Joules) in the resistor R until steady state is reached, is t = 0 :4F 592 N 2F

An LC circuit like that in the figure below consists of a 3.30-H inductor and an 836-pF capacitor that initially carries a 118-μC charge. The switch is open for t < 0 and is then thrown closed at t = 0. Compute the following quantities at t = 5.00 ms. 2max 000 (a) the energy stored in the capacitor (b) the total energy in the circuit (c) the energy stored in the inductor 0

Can you help me solve this? For two capacitors C1, C2 in series, with initial voltages (at t = 0-) V01 and V02, respectively, derive the instantaneous voltages v1(t) across C1 and v2(t) across C2 for t ≥ 0+in terms of C1, C2, V01, and V02.

My teacher said that the equation v(t) for Vcap (in image) will be V = -1/C integral of i(t) + v(initial). My question is, my teacher has said that the '-' infront of the 1/C is because the current flows into the negative terminal of the capacitor. But in the answer my teacher has put v(initial) as +20 and not -20, even though the 20V across the capacitor is also negative to positive as shown in the image. So why is the v(initial) put as +20 and not -20? Thank you.

During the transient analysis of an RL circuit, if the current through an inductor is 1.5 A at t = 0, the current through that inductor at t = (0.5 time-constant) will be: O A. Higher O B. The same O C. Lower O D. None of the other choices are correct O E. Can't tell the current until we know the voltage applied to the circuit

Asap please

Please answer all parts