MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- ou are tasked with finding a 95% confidence interval for a population mean. You do not know the standard deviation of the population, nor do you know its distribution. Your sample size is 23, and you have found the sample mean and sample standard deviation. Which of the following equations for the interval estimate endpoints should you use to find the confidence interval?arrow_forwarda. Use the one-mean t-interval procedure with the sample mean, sample size, sample standard deviation, and confidence level given below to find a confidence interval for the mean of the population from which the sample was drawn. b. Obtain the margin of error by taking half the length of the confidence interval. S c. Obtain the margin of error by using the formula ta/2 √n x=27 n=36 s=3 Click here to view Page 1 of the table of t-values with area alpha to its right. Click here to view Page 2 of the table of t-values with area alpha to its right. a. The 95% confidence interval about u is (Round to three decimal places as needed.) b. The margin of error found by taking half the length of the confidence interval is (Round to three decimal places as needed.) c. The margin of error found by using the formula is (Round to three decimal places as needed.) confidence level = 95%arrow_forwardAnswer part carrow_forward
- Shown below is the confidence interval (CI) for the difference, µ, - H2, between two population means. Interpret the confidence interval. 90% Cl is from 20 to 30 Choose the correct answer below. O A. It can be said, with 90% confidence, that there is no significant difference between the value of Hj and the value of lz. Note that this means the difference between the two means may be zero O B. It can be said, with 90% confidence, that the value of u, is somewhere between 20 and 30 less than the value of h. Note that this means the difference between the two means is less than zero. O c. It can be said, with 90% confidence, that the value of u, is somewhere between 20 and 30 greater than the value of µ. Note that this means the difference between the two means is greater than zero O D. The true value of l, - H, lies somewhere between 20 and 30. Note that this means the difference between the two means is greater than zero.arrow_forwardExb 9 and 10arrow_forwardThe weights of running shoes are normally distributed with an unknown population mean and standard deviation. If a random sample of 23 running shoes is taken and results in a sample mean of 12 ounces and sample standard deviation of 3 ounces, find the margin of error for a 95% confidence interval estimate for the population mean and construct the interval. Round the final answers to two decimal places. ME = C.I. = ( , )arrow_forward
- Need help with a 90% confidence interval and a 95% Confidence interval?arrow_forwardA random sample of 88 observations produced a mean x=25.8 and a standard deviation s=2.5. a. Find a 95% confidence interval for μ. b. Find a 90% confidence interval for μ. c. Find a 99% confidence interval for μ. a. The 95% confidence interval is (enter your response here,enter your response here).arrow_forwardThe following information is obtained for a sample of 80 observations taken from a population. SS xx 370.842, se = 0.922, and y = 164.43 - 2.83x Make a 97 % confidence interval for B. = Round your answers to two decimal places. The 97 % confidence interval for Bis ( i ).arrow_forward
- Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.arrow_forwardA laboratory tested 85 chicken eggs and found that the mean amount of cholesterol was 191 milligrams. Assume that o = 16.2 milligrams. Construct a 95% confidence interval for the true mean cholesterol content, µ, of all such eggs. Round to one decimal place. O A. 186.9 to 195.1 milligrams B. 186.5 to 195.5 milligrams C. 188.1 to 193.9 milligrams D. 187.6 to 194.4 milligramsarrow_forwardIf X=115, σ=22, and n=36, construct a 95% confidence interval estimate of the population mean, μ. Click here to view page 1 of the cumulative standardised normal distribution table. LOADING... Click here to view page 2 of the cumulative standardised normal distribution table. LOADING... The 95% confidence interval is enter your response here≤μ≤enter your response here. (Round to two decimal places as needed.)arrow_forward
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