Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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The problem presented on the educational website is as follows: 

"The specific heat of a certain type of metal is 0.128 J/(g°C). What is the final temperature if 305 J of heat is added to 28.0 g of this metal, initially at 20.0 °C?"

There is an interactive box for entering the answer, labeled as "T_final = _____ °C". An answer of "59.0 °C" was entered but marked as incorrect.

### Explanation:

To calculate the final temperature, we can use the formula for heat transfer:

\[ q = m \cdot c \cdot \Delta T \]

Where:
- \( q \) is the amount of heat added (305 J),
- \( m \) is the mass of the metal (28.0 g),
- \( c \) is the specific heat capacity (0.128 J/(g°C)),
- \( \Delta T \) is the change in temperature (\( T_{\text{final}} - T_{\text{initial}} \)).

Rearranging the formula to solve for \( T_{\text{final}} \):

\[ T_{\text{final}} = \frac{q}{m \cdot c} + T_{\text{initial}} \]

Substituting the given values:

\[ T_{\text{final}} = \frac{305 \, \text{J}}{28.0 \, \text{g} \cdot 0.128 \, \text{J/(g°C)}} + 20.0\, \text{°C} \]

Calculating the final temperature will provide the correct answer.
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Transcribed Image Text:The problem presented on the educational website is as follows: "The specific heat of a certain type of metal is 0.128 J/(g°C). What is the final temperature if 305 J of heat is added to 28.0 g of this metal, initially at 20.0 °C?" There is an interactive box for entering the answer, labeled as "T_final = _____ °C". An answer of "59.0 °C" was entered but marked as incorrect. ### Explanation: To calculate the final temperature, we can use the formula for heat transfer: \[ q = m \cdot c \cdot \Delta T \] Where: - \( q \) is the amount of heat added (305 J), - \( m \) is the mass of the metal (28.0 g), - \( c \) is the specific heat capacity (0.128 J/(g°C)), - \( \Delta T \) is the change in temperature (\( T_{\text{final}} - T_{\text{initial}} \)). Rearranging the formula to solve for \( T_{\text{final}} \): \[ T_{\text{final}} = \frac{q}{m \cdot c} + T_{\text{initial}} \] Substituting the given values: \[ T_{\text{final}} = \frac{305 \, \text{J}}{28.0 \, \text{g} \cdot 0.128 \, \text{J/(g°C)}} + 20.0\, \text{°C} \] Calculating the final temperature will provide the correct answer.
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