The solution of the differential equation subject to the initial conditions y(0) = 0 and y'(0) = −7 is y(x) = y" + 4y -4 cos(2x) + 28 sin(2x)

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Q: SOLVE STEP BY STEP IN DIGITAL FORMAT SOLVE BY SUBSTITUTION b) (y²+ yx)dx+x²dy = 0

A: The given differential equation is

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Q: =-4y1-2y2+t, y2=3y1 + y2-t, 31 (0) 5.75, 32 (0) = -6.75

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A: The answer is explained in belowExplanation:Step 1 Step 2:

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