The single-line diagram of a three-phase power system is shown in the below figure. Equipment ratings are given as follows: Synchronous generators: GI 1000 MVA x - X2 - 0.18, Xo -0.07 per unit X - X2 - 0.20, Xo =0.10 per unit X- X, -0.15, Xg- 0.05 per unit 15 kV G2 1000 MVA 15 kV G3 500 MVA 13.8 kV G4 750 MVA 13.8 kV X = 0.30, X2 - 0.40, Xo = 0.10 per unit Transformers: 15 kV A/765 kV Y X- 0.10 per unit X - 0.10 per unit X - 0.12 per unit X - 0.11 per unit TI 1000 MVA T2 1000 MVA 15 kV A/765 kV Y T3 500 MVA 15 kV Y/765 kV Y T4 750 MVA 15 kV Y/765 kV Y 3 T, Line 1-3 Line 1-2 Line 2-3 Transmission lines: 1-2 765 kV X = 50 2, Xo -150 N 1-3 765 kV X1 = 40 2, X, - 100 2 2-3 765 kV X = 40 2, X, = 100 2 The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as a base. Calculate the zero-, positive-, and negative-sequence reactance using a 1000- MVĀ, 765-kV base in the zone of line 1-2. Neglect the A-Y transformer phase shifts.

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Problem 1
The single-line diagram of a three-phase power system is shown in the below figure. Equipment
ratings are given as follows:
Synchronous generators:
GI 1000 MVA
15 kV
X - X2 - 0.18, Xo = 0.07 per unit
G2 1000 MVA
15 kV
X = X = 0.20, Xo = 0.10 per unit
G3 500 MVA
13.8 kV
x = X, = 0.15, X, = 0.05 per unit
G4 750 MVA
13.8 kV
X = 0.30, X2 = 0.40, X, = 0.10 per unit
Transformers:
TI 1000 MVA
15 kV A/765 kV Y
X = 0.10 per unit
T2 1000 MVA
15 kV A/765 kVY
X= 0.10 per unit
T3 500 MVA
15 kV Y/765 kV Y
X = 0.12 per unit
T4 750 MVA
15 kV Y/765 kVY
X = 0.11 per unit
T3
Line 1-3
Line 1-2
2
Line 2-3
Transmission lines:
1-2 765 kV
X¡ = 50 Q, X, = 150 N
1-3 765 kV
X = 40 N, X, = 100 .
2-3 765 kV
X1 = 40 Q, X, = 100 N
The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3
ratings as a base. Calculate the zero-, positive-, and negative-sequence reactance using a 1000-
MVA, 765-kV base in the zone of line 1-2. Neglect the A-Y transformer phase shifts.
石。
Transcribed Image Text:Problem 1 The single-line diagram of a three-phase power system is shown in the below figure. Equipment ratings are given as follows: Synchronous generators: GI 1000 MVA 15 kV X - X2 - 0.18, Xo = 0.07 per unit G2 1000 MVA 15 kV X = X = 0.20, Xo = 0.10 per unit G3 500 MVA 13.8 kV x = X, = 0.15, X, = 0.05 per unit G4 750 MVA 13.8 kV X = 0.30, X2 = 0.40, X, = 0.10 per unit Transformers: TI 1000 MVA 15 kV A/765 kV Y X = 0.10 per unit T2 1000 MVA 15 kV A/765 kVY X= 0.10 per unit T3 500 MVA 15 kV Y/765 kV Y X = 0.12 per unit T4 750 MVA 15 kV Y/765 kVY X = 0.11 per unit T3 Line 1-3 Line 1-2 2 Line 2-3 Transmission lines: 1-2 765 kV X¡ = 50 Q, X, = 150 N 1-3 765 kV X = 40 N, X, = 100 . 2-3 765 kV X1 = 40 Q, X, = 100 N The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as a base. Calculate the zero-, positive-, and negative-sequence reactance using a 1000- MVA, 765-kV base in the zone of line 1-2. Neglect the A-Y transformer phase shifts. 石。
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