The simply supported beam is subjected to the forces andmoment as shown in the diagram and table. Calculate theequivalent resultant load at point A. Take positive x to be tothe right, positive y to be up, and positive moment to becounterclockwise.F₁4₁parameterL₁L2F₁F₂F3M7//////77) Bvalue units4.54mmNNN403040250 N•m-L₂The resultant force in the x direction isThe resultant force in the y direction isThe resultant couple moment is(сс0602021 Cathy ZupkeDMN•mN

Given:Required:Equivalent resultant load at point A

The simply supported beam is subjected to the forces and moment as shown in the diagram and table. Calculate the equivalent resultant load at point A. Take positive x to be to the right, positive y to be up, and positive moment to be counterclockwise. F₁ L₁ parameter L₁ L2 F₁ F2 F3 M F₂ B value units 4.5 4 40 30 40 250 N•m m m N zz: N N -L₂ The resultant force in the x direction is The resultant force in the y direction is The resultant couple moment is BY NO SA 2021 Cathy Zupke F3 N•m N N

The simply supported beam is subjected to the forces and moment as shown in the diagram and table. Calculate the equivalent resultant load at point A. Take positive x to be to the right, positive y to be up, and positive moment to be counterclockwise. F₁ L₁ parameter L₁ L2 F₁ F2 F3 M F₂ B value units 4.5 4 40 30 40 250 N•m m m N zz: N N -L₂ The resultant force in the x direction is The resultant force in the y direction is The resultant couple moment is BY NO SA 2021 Cathy Zupke F3 N•m N N

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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