The simply supported beam consists of a W14 × 34 structural steel wide-flange shape [E = 29,000 ksi; I = 340 in.4]. For the loading shown, use discontinuity functions to compute (a) the slope of the beam at E and (b) the deflection of the beam at C. Assume w0 = 7 kips/ft, wCD = 3.5 kips/ft, LAB = 7.0 ft, LBC = 7.0 ft, LCD = 10.0 ft, LDE = 4 ft
The simply supported beam consists of a W14 × 34 structural steel wide-flange shape [E = 29,000 ksi; I = 340 in.4]. For the loading shown, use discontinuity functions to compute (a) the slope of the beam at E and (b) the deflection of the beam at C. Assume w0 = 7 kips/ft, wCD = 3.5 kips/ft, LAB = 7.0 ft, LBC = 7.0 ft, LCD = 10.0 ft, LDE = 4 ft
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The simply supported beam consists of a W14 × 34 structural steel wide-flange shape [E = 29,000 ksi; I = 340 in.4]. For the loading shown, use discontinuity functions to compute (a) the slope of the beam at E and (b) the deflection of the beam at C. Assume w0 = 7 kips/ft, wCD = 3.5 kips/ft, LAB = 7.0 ft, LBC = 7.0 ft, LCD = 10.0 ft, LDE = 4 ft.
![12:38
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The simply supported beam consists of a
W14 x 34 structural steel wide-flange
shape [E = 29,000 ksi; I = 340 in.4]. For the
loading shown, use discontinuity functions
to compute (a) the slope of the beam at E
and (b) the deflection of the beam at C.
Assume wo = 7 kips/ft, wcD = 3.5 kips/ft, LAB
7.0 ft, LBC = 7.0 ft, LCD = 10.0 ft, LDE = 4 ft.
=
Wo
WCD
X
B
LAB
Answer:
(a) 8E=
(b) vc=
Save for Later
LBC
LCD
D
LDE
rad
in.
844
E](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84b53a26-5e5f-4c86-b286-43a8b26e17a9%2Fbf6404e7-2df5-450f-bb1f-1ef52aa5f669%2Fy1b8ub_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12:38
KB/S
NWP Assessment Builder UI A...
← Assessment No. 6
3 of 10
<
>
- / 10
¹=
The simply supported beam consists of a
W14 x 34 structural steel wide-flange
shape [E = 29,000 ksi; I = 340 in.4]. For the
loading shown, use discontinuity functions
to compute (a) the slope of the beam at E
and (b) the deflection of the beam at C.
Assume wo = 7 kips/ft, wcD = 3.5 kips/ft, LAB
7.0 ft, LBC = 7.0 ft, LCD = 10.0 ft, LDE = 4 ft.
=
Wo
WCD
X
B
LAB
Answer:
(a) 8E=
(b) vc=
Save for Later
LBC
LCD
D
LDE
rad
in.
844
E
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