The Simple Pendulum A. H M Sketch a graph to show the predicted relationship. 22 H Task 8 In your group, discuss how to derive an equation to relate the initial pendulum height H to the bob's v 2 its lowest point. Show the derivation of the equation. Then, again, use your theoretical equation to calculate the expected (theoretical) slope. Use g = 9.79 ± 0.05 m/s2 expected change in the bob's kinetic energy and the expected change in the bob's potential energy during this motion? released from rest and moving from a high position to its lowest position

a.mheducation.com/ext/map/index.html?_con%3Dcon&external_browser%3D08&launchUrl=https%253A%252... Check my NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. The bob of a simple pendulum of length /= 40 in. is released from rest when 0 = 5°. Assuming simple harmonic motion, determine the magnitudes of the velocity and acceleration of the bob after the pendulum has been in motion for 1.65 s. The magnitude of the velocity of the bob after the pendulum has been in motion for 1.65 s is 82699 ft/s. The magnitude of the acceleration of the bob after the pendulum has been in motion for 1.65 s is t/s2. Menu Tro Dicection In fuel

Consider a pine wood shaft that is 8 ft long and has a diameter of 4 in. 2 What is the volume of the shaft (in ft³)? (Assume the shaft is cylindrical.) x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. ft3 What is the density of pine wood (see table below)? (Enter your answer in kg/m³.) Density, Specific Gravity, and Specific Weight of Some Materials (at room temperature or at the specified temperature) Material Solids Aluminum Asphalt Cement Clay Fireclay Brick Glass (soda lime) Glass (lead) Glass (Pyrex) Iron (cast) Iron (wrought) Paper Steel (mild) Steel (stainless 304) Wood (ash) Wood (mahogany) Wood (oak) Wood (pine) Density (kg/m³) Specific Gravity Specific Weight (N/m³) 26,880 2,740 2,110 1,920 1,000 1,790 @ 100°C 2,470 4,280 2,230 7,210 7,700 @100°C 930 7,830 7,860 690 550 750 430 2.74 2.11 1.92 1.00 1.79 2.47 4.28 2.23 7.21 7.70 0.93 7.83 7.86 0.69 0.55 0.75 0.43 20,700 18,840 9,810 17,560…

I received an answer for my last question and I am still a bit confused. In the solution you said that F only has a horizontal component, how did you arrive at that? The question says that F is down and to the left.