The signs shown held up by cable ABCD. The weight of the university logo sign is 200 lb and the weight of the college logo sign is 100 lb. The cable between points B and C is parallel to X-axis. The two signs are in equilibrium conditions. Find the tension force at points A, B, C, D and the angles a and ẞ. Hint: Point A and point D have the same Y coordinate (3.38'). No reaction forces at Point A and point A a 35' B C β & Computer Science and Engineering GRIZZLIES 10 D

Parallel Forces in Space. Show complete solution

An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F1=200 lbf, F2=250 lbf, and F3=100 lbf with 0 = 30 degrees and p=24.1 degrees. If the eye bolt is in equilibrium, what is the x-component of the sum of other forces on the bolt (force from the nut and plate on the bolt) ? If you add up the three force vectors, the sum other force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The x-direction is positive to the right. For example, if you find the sum of forces 1, 2, and 3 are 100 Ibf to the right, then the other forces in the x-direction must be pointing to the left (-100 lbf) to put the eye bolt in equilibrium. Eye bolt 2steel 3 plate Nut t Wonsher

A weight W= 120 kN is being supported by steel sections with force T, force F, and force C. The coordinates of A, B, C, and D are given. Assume that E is the origin (0,0,0). Determine Forces T, F, and C. (Hint: Produce three equations from equilibrium of force system)

TOPIC #6: FRAMES/MACHINES Given the frame to the right. B is a pinned end and A is a fixed end. Find all of the reaction forces/moments. E 4 ft V 70 Ibs 4 ft B. - 3 ft 3 ft-

An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F1=200 lbf, F2=250 lbf, and F3=100 Ibf with 0 = 30 degrees and p=44 degrees. If the eye bolt is in equilibrium, what is the y-component of the sum of other forces on the bolt (force from the nut and plate on the bolt) ? If you add up %3D the three force vectors, the sum other force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The y-direction is positive going up. For example, if you find the sum of forces 1, 2, and 3 are 100 Ibf going up, then the other forces in the y-direction must be pointing to the down (-100 lbf) to put the eye bolt in equilibrium. Eye bolt steel plate Nut & Washer esc DOO D00 F4 F3 AA %24 F10

Physics for Engineering A uniform bar 3.00 m long is held by ropes at the ends making angle 60.0 and 30.0, respectively, with the horizontal. A weight of 200 N is hung 0.500 m from the left end where the 60.0 rope is attached. Find the tension in the ropes (T1 & T2) and the weight (W) of the bar. (Hint: Formulate three equations for the three unknowns, 2 equations for the 1st condition and 1 equation for the 2nd condition.)

The given system is in static equilibrium with the strings AB, BC, and CD connected to support the 40N and 50N weights. The middle string BC is exactly horizontal, and points A and D are connected to a rigid support. Calculate the tension forces T{1}, T{2}, T{3} and the angle theta?

Question The traffic light shown below is supported by a system of cables. Points A and B are in a vertical plane which is parallel to the x-z plane. Point C is in the y-z plane. B Z The traffic light has a mass of 75 kg The distances are: a = 4m, b = 6 m, c = 9 m, h = 6 m Find the tensions (in Newtons) in cables OA, OB and OC. h

The man in the picture below has a weight (not a mass) of 600Newtons. Find the tension in all three ropes. Hint: draw two free body diagrams, one for the man, one for the "knot" where the three ropes join together. 37.0° 600 N