5.4 The sieve analysis of ten soils and the liquid and plastic limits of the fractionpassing through the No. 40 sieve are given below. Classify the soils by theAASHTO classification system and give the group index for each soil.Soil12345678910Sieve analysis-Percent finerNo. 10No. 40No. 20098100100859297100948310080928855756055804892K5080654562308632086Liquid limit Plasticity index385637284325402070292322202816NP211538

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The sieve analysis of ten soils and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils by the AASHTO classification system and give the group index for each soil. Soil 1 98 2 100 3 100 4 85 92 97 100 94 83 100 5 6 Sieve analysis-Percent finer No. 10 No. 40 No. 200 7 8 9 10 80 92 88 55 75 60 55 80 48 92 50 80 65 45 62 30 8 63 20 86 Liquid limit Plasticity index 38 56 37 28 43 25 40 20 70 29 23 22 20 28 16 NP 21 15 38

The sieve analysis of ten soils and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils by the AASHTO classification system and give the group index for each soil. Soil 1 98 2 100 3 100 4 85 92 97 100 94 83 100 5 6 Sieve analysis-Percent finer No. 10 No. 40 No. 200 7 8 9 10 80 92 88 55 75 60 55 80 48 92 50 80 65 45 62 30 8 63 20 86 Liquid limit Plasticity index 38 56 37 28 43 25 40 20 70 29 23 22 20 28 16 NP 21 15 38

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Soil classification and characteristics

Soil classification is a method of categorizing soil based on its properties, types, and uses. The motive of soil classification is to arrange various types of soils and divide them into groups for various engineering and agricultural purposes. Soil classification is carried out by various agencies as per their purposes. From an engineering perspective, soil classification is done to find out the suitability of soil for various construction purposes like the construction of dams, foundations, highways, infrastructures, and so on. For engineering purposes, the soil is classified by the following systems:

Question

5.4 The sieve analysis of ten soils and the liquid and plastic limits of the fraction
passing through the No. 40 sieve are given below. Classify the soils by the
AASHTO classification system and give the group index for each soil.
Soil
1
2
3
4
5
6
7
8
9
10
Sieve analysis-Percent finer
No. 10
No. 40
No. 200
98
100
100
85
92
97
100
94
83
100
80
92
88
55
75
60
55
80
48
92
K
50
80
65
45
62
30
8
63
20
86
Liquid limit Plasticity index
38
56
37
28
43
25
40
20
70
29
23
22
20
28
16
NP
21
15
38

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Problem 2. The sieve analysis of ten soils and the liquid and plastic limits of the fraction pass- ing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. Soll No. 567699AWN. 4 8 10 No. 10 98 100 100 85 92 48 87 90 100 92 Sleve analysis (percent finer) No. 40 80 92 88 55 75 28 62 76 78 74 No. 200 50 80 65 45 62 6 30 34 8 32 Liquid limit 38 56 37 28 43 32 37 44 Plastic limit 29 23 22 20 28 NP 24 25 NP 35
Question 3 The sieve analysis of soil and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. % Passing No. 10: 48 % Passing No. 40: 28 % Passing No. 200: 6 LL = - %3D PL = NP Group classification: Blank 1 Group index: Blank 2
The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
Given the following Sieve Analysis and Atterberg limits results. Answer the following questions: 1- What is the effective diameter of this soil? 2- Calculate the uniformity coefficient and coefficient of gradation 3- Determine the percentage of Gravel, Sand, Fine soils according to USCS. 4- Classify the soil using AASHTO (with GI) & USCS (with group name). Diameter Sieve # % Passing 100 (тm) 90 4 4.75 96 80 3.35 90 70 10 78.8 60 20 0.85 56.8 50 40 0.425 37.8 40 60 0.25 23.6 30 100 0.15 13 20 200 0.075 4.6 10 Рan LL 10 10 0.1 0.01 Diameter PL 5 Percent Passing (%) 2.
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% Finer • Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle size distribution curves are shown in Figure 100 90 80 70 60 50 40 30 Clay 20 10 0 0.001 + Silt 0.01 Soil A Sand Soil B 0.1 1 Particle size (mm) - log scale Gravel 10 Soil A LL 26 (oven-dried; assume same for not dried) B Nonplastic 1. Which of the two soils, in your opinion, is a better material for the core of a rolled earth dam? PL 18
From your Atterberg limits tests on the -40 portion of these samples, you have obtained the following data Percentage finer by weight 100% 80% 60% 40% 20% 0% Soil Sample Identification 0.001 H I J L FINES Liquid Limit 60 H 0.010 46 37 Plastic Limit 26 nonplastic #200 34 18 Fine HOT SAND Medium 0.100 Particle size (mm) 1.000 GRAVEL Course Fine Coarse #4 10.000 Classify the soils H, I, J and L using 1) USCS Classification 2) AASHTO Classification 3" 100.000 I LLII. I
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2. The result of sieve analysis of three soils is given. It is required to classify these soils according to the AASHTO Classification System. Sieve No. 4 8 10 20 40 60 100 200 LL PL Diam. (mm) 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 SIEVE ANALYSIS Soil A 90 64 55 33 24 17 9 5 Percent Passing Soil B 100 90 77 59 50 42 36 33 46 29 Soil C 100 100 78 91 85 79 70 63 47 24 a. What is the classification of Soil A? b. What is the classification of Soil B? c. What is the classification of Soil C?
Q1: Use the USCS to Classify the soil sample with the following data: % passing 4.75 mm Sieve = 64 % passing 75- Sieve =4 Uniformity Coefficient= 7.5 Coefficient of Curvature=2.7 Plasticity index = 2.5 Solution: Q2: Use the USCS to Classify the soil samples with the following data dalla Soil LL PL Group Symbol Soil Name 15 35 25 ABC 8. ८८ 25 45 65 2-Seepage velocity (m/s) = 70 3- Flow rate in (m3/s) = oss and dry ng www Parmbly & volume change decrease Campering wes Toughness and dry strength dease Presby & val change in 10 20 30 40 50- 60 Liepakt. 70 80 Atra -0.73 (W₂-201 90 Q3: For the soil shown below the hydraulic conductivity is (3 m/day). The sample diameter is 1.5 m. The porosity is (30%). Find: 1- Flow velocity (m/s)== 100 110 120 Soil 4 m ITE
Classify the following soils by the Unified soil classification system. Give the group na soil Soil 1 2 Sieve analysis (percentage finer) Liquid Plastic No. 4 No. 200 limit limit 98 28.5 33.2 22.6 95 10 30 22 D10 D30 8 D60 0.085 0.12 0.135 Q1)
The sieve analysis of four soils and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. Comment on the suitability of the soils as subgrade material. Sieve analysis (percent finer) Soil No. No. 10 No. 40 No. 200 Liquid limit Plastic limit 100 80 58 30 20 2 95 60 20 3 90 76 34 37 25 4 48 28 NP [Das B. M. Principles of Geotechnical Engineering (7E), pp. 101, 102, 112]