The sample data below have been collected based on a simple random sample from a normally distributed population. Complete parts a and b. 4 9 2 9 4 a. Compute a 90% confidence interval estimate for the population mean. The 90% confidence interval for the population mean is from (Round to two decimal places as needed. Use ascending order.) to

n1=16 x‾1=124 s1=35   n2=12 x‾2=86 s2=31 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 :   Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3 : Please also find the high and low endpoints and round to four decimal points.

Given two independent random samples with the following results: n₁ = 16 n₂ = 8 x₁ = 94 X2: $₁ = 16 = 124 $2 = 28 Use this data to find the 90% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Copy Data Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.

Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"

Also included in question find estimated variance of errors, estimated variance of slope, and 90% and 95% confidence intervals for slope. Thank you so much

You are interested in finding a 90% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 14 randomly selected non-residential college students. Round answers to 3 decimal places where possible.   5 8 11 10 12 19 24 6 26 10 26 10 26 15   a. To compute the confidence interval use a     distribution. b. With 90% confidence the population mean commute for non-residential college students is between  and   miles. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About  percent of these confidence intervals will contain the true population mean number of commute miles and about  percent will not contain the true population mean number of  commute miles.

Use the data to calculate the sample variance, s. (Round your answer to five decimal places.) n = 7: 1.6, 3.5, 1.6, 2.1, 3.1, 2.9, 3.0 %3D Construct a 95% confidence interval for the population variance, of. (Round your answers to two decimal places.) to Test Ho: = 0.8 versus H: of + 0.8 using a = 0.05. State the test statistic. (Round your answer to two decimal places.) x2 State the rejection region. (If the test is one-tailed, enter NONE for the unused region. Round your answers to two decimal places.) x2 > x² State the conclusion. H, is rejected. There is sufficient evidence to indicate that the population variance is different from 0.8. H, is rejected. There is insufficient evidence to indicate that the population variance is different from 0.8. H, is not rejected. There is sufficient evidence to indicate that the population variance is different from 0.8. O Ho is not rejected. There is insufficient evidence to indicate that the population variance is different from 0.8.

Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96

Given two independent random samples with the following results: n₂ = 8 x₂ = 175 $2 = 11 n₁ = 12 x₁ = = 157 $₁ = 32 Use this data to find the 95% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 1 of 3: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.