The σ - ε diagram for elastic fibers is shown. (Figure 1) Figure 385 σ(MPa) 77 < 1 of 1 €(mm/mm) 1 2 2.25 Part A Determine the modulus of elasticity of the fibers. Express your answer using three significant figures. Part B Estimate their modulus of toughness. Express your answer using three significant figures. Part C Estimate their modulus of resilience. Express your answer using three significant figures.

C1=150 C2=110

Rigid bar ABCD is loaded and supported. Steel [E=30,000 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar (1) has a cross-sectional area of 0.625 in.2 and bar (2) has a cross-sectional area of 1.25 in. 2. After load P is applied, the strain in bar (2) is found to be 900 με. If there is a clearance of 0.05 in. in the pin connection at C, determine: (a) the stresses in bars (1) and (2).(b) the vertical deflection of point D.(c) the load P.

Find the breaking point along the fishing rod assuming that the base of the rod is in a fixed position and will not move. The rod is made out of Carbon fiber with diameters a=9.93 mm wide, b=7.13mm wide, and c=5.1mm wide. The total length of the rod is 2 meters. The modulus of elasticity of Carbon Fiber is 228 Gpa. Find what force "F" is needed to break the fishing rod assuming that the force is acting straight along the line. | 100 45 F

1. Arectangular plate 50 mm x 10 mm with a hole 10 mm diameter is subjected to an axial load of 10KN. Taking stress concentration into account, find the maximum stress induced. [Ans. 50 MPa]

Compute the modulus of elasticity  for a composite which uses High Modulus Carbon fibers and Polyester matrix. The volume fraction of fibers is  45 % and matrix is 55 %.  Note-use chart in image

calculate the modulus of elasticity for material 1

Mechanics of materials I

I NEED ANSWERS AASAP THANK YOU!!

I need to calculate the tensile stiffness along the fibre which have a length of 250um  below are the values ive been given Matrix Stiffness Em = 6 GPaMatrix Strength (sigma)m = 50 MPaFibre Volume Fraction 0.41Fibre Stiffness Ef = 49 GPaFibre Strength (sigma)f = 103 MPaFibre Shear Stiffness  Gf = 23 GPaMatrix Shear Stiffness Gm = 2 GPaInterface Strength ti = 7 MPaFibre Diameter = 7um poissons ratio of matrix = 0.32Poissons ratio of fibre = 0.23tensile stress of 190 MPa applied at an angle of 60 degrees. it is a unidirectional composite.