The rod AB shown below moves horizontally as guided by two small wheels rolling on a frictionless slot. If P = 15 N, solve for the reactions at A and B. The mass of the rod is 2.75 kg. The center of mass of the body is located 2r/pi vertically and horizontally %3D from the intersection of the vertical axis at A and horizontal axis at B. В P
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- SECW OM A motorbike wheel with an 8 kg mass has a 0.4 m radius of gyration around the z-axis, as shown in Figure. The wheel's shaft is supported by bearings A and B and rotates at a constant rate of 150 rpm in a counter-clockwise direction from the z-axis, while the frame rotates at 12 rpm in a counter- clockwise direction from the y-axis. Determine the resultant reaction forces at each bearing A and B due to the mass and gyroscopic effects. With the result of forces, which bearing has a tendency to fail first, which bearing should be considered for design purposes and explain the effect on motor if the bearing fail. y 0.55 0.4 All dimensions in meter (m)4. A thin homogeneous plate has a mass of 10 lb and is welded to a light vertical axel AB supported top and bottom by bearings. If the plate rotates at a constant rate of 3000 rpm, what are the reactions at the bearings, as vectors? В 24 in. A e 12 in.2.5 m 3.0 m 4000 N m 2.5 m 300 N 2 m 30° A smooth and weightless rod is subject to a force on one end and a moment at its mass center. If the Uniform rod is supported at multiple points as shown in the picture, find the reaction forces at these supports. Assume that the rod is supported at point A by a smooth wall and at B and C either at the top OR bottom by rollers. On your answer sheet provide the FBD and all your calculations.
- The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1m B 0.5 m E .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kgThe bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1m B 0.5 m .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg (a) Since the moment arms from the axis toTg and W are easy to obtain, we can determine this result using a scalar analysis. As shown, Fig. b EMDA = 0; TR(1 m sin 45°) – 981 N(0.5 m sin 45°) = 0 ATB T = 490.5 N B IB 45°- 0.5 m W = 981 N TE Dy 0.5 m Ip. (b)The uniform L-shaped bar pivots freely at point P of the slider, which moves along the horizontal rod. Determine the steady-state value of the angle 0 if (a) a = 0 and (b) a = 0.68 g. For what value of a would the steady-state value of 0 be zero? 2.1 b Answers: (a) a = 0: i (b) a = 0.68g: 0 = i %3D The steady-state value of 0 will be zero when a = i bo
- The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1m B. 0.5 m Free-Body Diagram. As shown in Fig. b, there are six unknowns 05 m Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 00 kg (a) Since the moment arms from the axis to T, and W are easy to obtain, we can determine this result using a scalar analysis. As shown,Fig. b EMDA = 0; Tạ(1 m sin 45°) – 981 N(0.5 m sin 45°) = 0 T = 490.5 N 0.5 m W 981 N 05 m D, (b)The compound pulley shown has a weight of 1600 N and the radius of gyration (k = 2 m). Find the tension in the cord supporting the 1500-N weight (TA) and tension supporting the 2000-N weight (TB) as shownA spring with squared and ground ends has 16 active coils diameter of 6 mm and pitch of 10 mm . If spring rate is 85 KN/m , determine the solid force?
- The weight of the limb is W=15 lbs.The contact of foot with the ground can be modeled as a pin/hinge here. Determine the reaction force of the ground and the reaction at the knee joint and its direction/angle θ. Note: use the thee force member condition to find the angle of FK.Q4.As it’s been shown in the below figure,a person is using an exercise machine. Points A and B correspond to the shoulder and elbow joints, respectively. Relative to the person, the upper arm (AB) is extended toward the left (x-direction) and the lower arm (BC) is extended forward (z-direction). At this instant, the person is holding a handle that is connected by a cable to a suspending weight. The weight applies an upward (in the y-direction) force with magnitude F on the arm at point C. The lengths of the upper arm and lower arm are AB̅̅̅̅= 20cm and BC̅̅̅̅= 25cm, respectively, and the magnitude of the applied force is F = 400 N.Determine the components of reaction developed at the shoulder joint A When the…L.A tractor of mass 1200 kg is used to lift gravel weighing 8 KN. Determine the reaction at each of the front wheel. 8 KN 500 mm 1000 mm 1250 mm 2. A fixed crane, as given in figure, has a mass of 1000 kg and is used to lift a 2400-kg crate. It is held in place by a pin at A and a roller at B. The center of gravity of the crane is located at G. Determine the components of the reactions at A and B. 2400 kg 15 i 4m 3. Determine whether the block shown is in equilibrium and find the magnitude and direction of the friction force when 0-25 and P-750N. 1200 N H, -0.35 H=0.25The wheels, axle, and handles of a wheelbarrow W=62N. The load chamber and its contents weigh Wl=575N. The drawing chose leave to Forsyth and different wheelbarrow designs to support the wheelbarrow and equilibrium the man's hands apply a force to the handles that is directly vertically upward. consider the rotational axis at the point where the tire contacts the ground, directed perpendicular to the plane of the paper. Find the magnitude of the Man's force for both designs