The results from a compaction test are as follows: 130.0 128.0 126.0 124.0 122.0 120.0 118.0 116.0 114.0 112.0 4 8 10 12 14 16 18 20 Moisture Content (w%) a) What is the maximum dry unit weight and optimum moisture content? Use your best approximation. b) Ben wants to put in an awesome hot tub in his sloped backyard. To do so, it requires construction of an embankment with 1000 ft 3 of soil compacted to specifications of 95% relative compaction. The soil at the excavation site has a dry unit weight of 114 pcf with a moisture content of 6%. How much soil must be excavated to allow Ben to enjoy his hot tub? c) How much weight of water must be added to the excavated soil to facilitate compaction to the specifications of 95% relative compaction at dry of optimum. Dry Unit Weight (pcf)

The results from a compaction test are as follows: 130.0 128.0 126.0 124.0 122.0 120.0 118.0 116.0 114.0 112.0 4 8 10 12 14 16 18 20 Moisture Content (w%) a) What is the maximum dry unit weight and optimum moisture content? Use your best approximation. b) Ben wants to put in an awesome hot tub in his sloped backyard. To do so, it requires construction of an embankment with 1000 ft 3 of soil compacted to specifications of 95% relative compaction. The soil at the excavation site has a dry unit weight of 114 pcf with a moisture content of 6%. How much soil must be excavated to allow Ben to enjoy his hot tub? c) How much weight of water must be added to the excavated soil to facilitate compaction to the specifications of 95% relative compaction at dry of optimum. Dry Unit Weight (pcf)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q3. (a) The following results are obtained from a Standard Proctor compaction test: Mass of soil (kg) Moisture content (%) 1.791 8.4 1.937 10.6 2.038 12.9 2.050 14.4 2.022 16.6 1.985 18.6 The specific gravity of the solids is 2.70, pw= 1000kg/m' and the volume of the compaction mould is 0.945 x 10° m'. Plot the compaction curve and obtain the maximum dry density (MDD) and optimum moisture content (OMC).
Two days after heavy rain a 100 g soil sample was collected. The size of the remaining hole was 70 cm3. The air-dry soil weighs 80 g and contains 10% hygroscopic water. Calculate the oven-dry weight, the percentage of capillary water, bulk density and the percentage of pore space. Assume a particle density of 2.65 g/cm3
Gs 2.68. Determine (at optimum moisture content):a. Void ratiob. Degree of saturation
6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 1 943.3 1.68 9.9 943.3 1.71 10.6 3 943.3 1.77 12.1 4 943.3 1,83 13.8 943.3 1.86 15.1 6 943.3 1.88 17.4 943.3 1.87 19.4 8 943.3 1.85 21.2
SG is 2.66 and temperature is 18 degrees celcius
A sample soil is obtained and sieve analysis is performed to determined its particle distribution. Sieve Opening Mass Retained % Finer # 6 3.35 146 # 8 2.36 88 #16 1.18 125 # 40 0.425 56 #50 0.3 42 #140 0.106 127 # 200 0.075 126 Pan 29 Determine: 1. Effective Size (in mm and in 4 decimal places) 2. Uniformity Coefficient (in 2 decimal places) 3. Coefficient of Curvature (in 2 decimal places) 4. Sorting Coefficient (in 2 decimal places)
1.5 cm datum The following are the results of a compaction test; Mass of mold+wet soil(g) 2925 3095 3150 3125 3070 Water content% 10 12 14.3 16.1 18.2 If the volume of mold = 1000 ml, and mass of mold = 1000 g, and Specific gravit of solids = 2.70. G4 Wc a. Find the compaction curve showing the optimum moisture content and maximu dry density. b. Plot the zero air void line. c. Determine the degree of saturation at the maximum dry density. Sr P COONCOM
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For a soil specimen, given the following: % passing sieve #4-92 %, sieve #10 -81%, sieve # 40-78%, LL-48%, PL-16%, GI-18.2 classify the soil by AASHTO classification system. GI = (F200-35)[0.2 + 0.005 (LL - 40)] +0.01 (F20015)(PI – 10)
Please kindly answer all. C and d answers mandatory. Please answer all and help me.. thank you
Question 11 The results of the particle-size analysis of a soil are as follows: Percent passing the No. 10 sieve = 80 • Percent passing the No. 40 sieve = 40 Percent passing the No. 200 sieve = 20 %3D The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 30 and 5, respectively. Classify the soil by the AASHTO system. A A-2-4 B А-2-6 C) A-3 D A-2-5