The resistivity of copper is 1.70 x 10-8 2. m. HINT Apply the expression relating resistance to resistivity. Treat the wire as a cylinder with volume V = Al where A is the wire's cross-sectional area. Click the hint button again to remove this hint. (a) Find the resistance of a copper wire (in ohms) with a radius of 1.21 mm and a length of 1.18 m. Q (b) Calculate the volume (in m³) of copper in the wire. m3 (c) Suppose that volume of copper is formed into a new wire with a length of 2.92 m. Find the new resistance of the wire (in ohms). Ω

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
100%
### Understanding Resistance and Volume of a Copper Wire

#### Problem Statement:
The resistivity of copper is \( 1.70 \times 10^{-8} \, \Omega \cdot \text{m} \).

##### Hint:
Apply the expression relating resistance to resistivity. Treat the wire as a cylinder with volume \( V = A\ell \) where \(A\) is the wire's cross-sectional area.

**Click the hint button again to remove this hint.**

---

1. **Find the resistance of a copper wire (in ohms) with a radius of \(1.21 \, \text{mm}\) and a length of \(1.18 \, \text{m}\).**

   \( \boxed{\phantom{0}} \, \Omega \)

2. **Calculate the volume (in m³) of copper in the wire.**

   \( \boxed{\phantom{0}} \, \text{m}^3 \)

3. **Suppose that volume of copper is formed into a new wire with a length of \(2.92 \, \text{m}\). Find the new resistance of the wire (in ohms).**

   \( \boxed{\phantom{0}} \, \Omega \)

---

In this problem, you are required to apply the concepts of resistivity and geometric properties of cylindrical objects to solve for the resistance and volume of a copper wire and its transformation when the dimensions are altered. Here's a step-by-step method to solve the questions:

- **Resistance Calculation:**
  The resistance \(R\) of a wire is calculated using the formula:
  \[
  R = \rho \frac{\ell}{A}
  \]
  where:
  - \( \rho \) is the resistivity of the material (\( 1.70 \times 10^{-8} \, \Omega \cdot \text{m} \) for copper)
  - \( \ell \) is the length of the wire
  - \( A \) is the cross-sectional area of the wire
  - The cross-sectional area \( A \) of a wire with radius \( r \) is given by \( A = \pi r^2 \)

- **Volume Calculation:**
  The volume \( V \) of the cylinder (wire) can be found using the formula:
  \[
  V = A\ell = \
Transcribed Image Text:### Understanding Resistance and Volume of a Copper Wire #### Problem Statement: The resistivity of copper is \( 1.70 \times 10^{-8} \, \Omega \cdot \text{m} \). ##### Hint: Apply the expression relating resistance to resistivity. Treat the wire as a cylinder with volume \( V = A\ell \) where \(A\) is the wire's cross-sectional area. **Click the hint button again to remove this hint.** --- 1. **Find the resistance of a copper wire (in ohms) with a radius of \(1.21 \, \text{mm}\) and a length of \(1.18 \, \text{m}\).** \( \boxed{\phantom{0}} \, \Omega \) 2. **Calculate the volume (in m³) of copper in the wire.** \( \boxed{\phantom{0}} \, \text{m}^3 \) 3. **Suppose that volume of copper is formed into a new wire with a length of \(2.92 \, \text{m}\). Find the new resistance of the wire (in ohms).** \( \boxed{\phantom{0}} \, \Omega \) --- In this problem, you are required to apply the concepts of resistivity and geometric properties of cylindrical objects to solve for the resistance and volume of a copper wire and its transformation when the dimensions are altered. Here's a step-by-step method to solve the questions: - **Resistance Calculation:** The resistance \(R\) of a wire is calculated using the formula: \[ R = \rho \frac{\ell}{A} \] where: - \( \rho \) is the resistivity of the material (\( 1.70 \times 10^{-8} \, \Omega \cdot \text{m} \) for copper) - \( \ell \) is the length of the wire - \( A \) is the cross-sectional area of the wire - The cross-sectional area \( A \) of a wire with radius \( r \) is given by \( A = \pi r^2 \) - **Volume Calculation:** The volume \( V \) of the cylinder (wire) can be found using the formula: \[ V = A\ell = \
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Combination of resistance
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON