The relative compaction of a sand in the field is 94%. Given that yalmax) = 16.9 KN/m, and ydlmin) = 14.4 kN/m3, what is the dry unit weights in the field and the relative density of compaction?
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- 7. The relative compaction of a sand in the field is 94%. Given that dry unit weight max = 16.2 kN/m3 and dry unit weight min = 14.9 kN/m3 . For the field conditions. What is the relative density compaction? (Ans: 27%) What is the dry unit weight? (Ans: 15.23 kN/m3) What is the moist unit weight at a moisture content of 10%? (Ans: 16.45 kN/m3 )6. The relative compaction of a sand in the field is 93.5%. Given that dry unit weight max = 16.98 kN/m3 and dry unit weight min = 14.46 kN/m3. What is the dry unit weights in the field? (Ans: 15.88 kN/m3) What is the relative density compaction? (Ans: 60.1%) What is the water content of the sand if the moist unit weight is 18.42 kn/m3. (Ans: 16%)8. The max and min dry unit weights of the sand were determined in the laboratory to be 16.5 kN/m3 and 14.6 kN/m3 respectively. The relative density of compaction in the field of the same sand is 70%. What is the relative compaction? (Ans: 96%) What is the dry unit weight? (Ans: 15.84 kN/m3 ) What is the moist unit weight at a moisture content of 10%. (Ans: 17.42 kN/m3 )
- From the following data, solve for the degree of compaction. If this is for Item 201, Aggregate Base Course, will it pass the specification? Field density test data: Weight of material taken from hole, kg. = Weight of sand to fill hole, kg. = 5.585 3.935 Volume of hole, cu.m = Wet unit weight, kg/cu.m = Dry unit weight, kg/cu.m = 0.0028 1995 1734 Laboratory Data: Maximum dry density, kg/cu.m. = 1750 Optimum Moisture Content, % = 8.001. A wet sand sample has a volume of 4.64 x 10⁻⁴ and weighs 8N. After oven drying, the weight reduces to 7.5N. Calculate the water content, void ratio and degree of saturation.(use Gs = 2.7) 2. A contractor has compacted the base course for a new road and found that the mean value of the test sample shows, w = 14.6%, Gs =2.81, and γ= 18.2 KN/m³. The specification require thate ≤0.8. has the contractor complied with the specifications? 3. The moist unit weight of soil is 16.5 KN/m³. Given that the w=15% and Gs = 2.70. Find:1) dry unit weight2) porosity3) degree of saturationThe maximum and minimum dry unit weights of a sand were determined in the laboratory to be 16.9 kN/m³ and 14.2 kN/m³, respectively. If the field relative density is 82%? Determine The degree of compaction in the field. Field dry unit weight. Field bulk unit weight if the field moisture content is 15%.
- Need complete solution. Need fast! The maximum and minimum dry densities of a sand were determined in the laboratory to be 1509 kg/m3 and 1673 kg/m3, respectively. In the field, if the relative density of compaction of the same sand is 86.83%, what is the relative compaction (in percent)? Round off to two decimal places.The relative compaction of a silty sand in the field is 94%. Given that γd(max) = 17 kN/m3 and γd(min) = 13.8 kN/m3 , determine the dry unit weight in the field and the relative density of compaction.A. The maximum and minimum dry unit weights of a sand were determined in the laboratory to be 104 lb/ft and 93 lb/ft, respectively. What would be the relative compaction in the field if the relative density is 78%? Q1 B. Given Gs = 2.65, calculate the zero-air-void unit weight for a soil in lb/ft at W = 10%.
- Estimate the value of coefficient of permeability for a uniform graded sand of size D₁0 = 0.15 mm obtained from sieve analysis. G = 2.67. 10the maximum and minimum dry unit weights of a sand were determined in the laboratory to be 17.5kn/m^3 and 14.8kn/m^3. what should be the relative compaction in the field if the relative density is 70%?Two specimens of clay A and B are tested in a consolidated apparatus. If: (mv) A = 3.6 x 10-4 m²/kN (m₂) = 1.8 x 10-4 m²/kN B (C₂)A = 3.8 x 10-4 cm²/s (C₂) A = 1.9 x 10-4 cm²/s then the ratio KA / KB is equal to