Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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**Infinite Series Representation of 0.9**

The real number 0.9 can be written as an infinite series as shown:

\[ 0.9 = \frac{9}{10} + \frac{9}{100} + \frac{9}{1000} + \cdots \]

**Instructions**

Write the infinite series in sigma notation and use the formula for the sum of a geometric series to find the sum.

---

**Explanation:**

The image above demonstrates how the number 0.9 can be expressed as an infinite series. Each term in the series is a fraction where the numerator is 9, and the denominator is a power of 10. This can be generalised in sigma notation.

In sigma notation, the series can be written as:

\[ 0.9 = \sum_{n=1}^{\infty} \frac{9}{10^n} \]

This series is a geometric series where the first term \(a = \frac{9}{10}\) and the common ratio \(r = \frac{1}{10}\).

The sum \(S\) of an infinite geometric series is given by the formula:

\[ S = \frac{a}{1 - r} \]

Plugging in the values for \(a\) and \(r\):

\[ S = \frac{\frac{9}{10}}{1 - \frac{1}{10}} = \frac{\frac{9}{10}}{\frac{9}{10}} = 1 \]

Thus, the sum of the infinite series is 1.
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Transcribed Image Text:**Infinite Series Representation of 0.9** The real number 0.9 can be written as an infinite series as shown: \[ 0.9 = \frac{9}{10} + \frac{9}{100} + \frac{9}{1000} + \cdots \] **Instructions** Write the infinite series in sigma notation and use the formula for the sum of a geometric series to find the sum. --- **Explanation:** The image above demonstrates how the number 0.9 can be expressed as an infinite series. Each term in the series is a fraction where the numerator is 9, and the denominator is a power of 10. This can be generalised in sigma notation. In sigma notation, the series can be written as: \[ 0.9 = \sum_{n=1}^{\infty} \frac{9}{10^n} \] This series is a geometric series where the first term \(a = \frac{9}{10}\) and the common ratio \(r = \frac{1}{10}\). The sum \(S\) of an infinite geometric series is given by the formula: \[ S = \frac{a}{1 - r} \] Plugging in the values for \(a\) and \(r\): \[ S = \frac{\frac{9}{10}}{1 - \frac{1}{10}} = \frac{\frac{9}{10}}{\frac{9}{10}} = 1 \] Thus, the sum of the infinite series is 1.
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