The readings obtained from a two-peg test carried out on an automatic level with a staff placed on two pegs A and B 50 m apart are: With the level midway between A and B Staff reading at A = 1.283 m %3D Staff reading at B = 0.860 m %3D • With the level positioned 5 m from peg B on line AB extended Staff reading at A = 1.612 m 1.219 m Staff reading at B = %3D Calculate the collimation error of the level per 50 m sighting distance and the hori- zontal reading that should be observed on the staff at A with the level in position 5 m from B.

The following staff readings were observed successively with a level. The instrument has been shifted after the second and fifth reading: 0.675, 1.230, 0.750, 2.565, 2.225, 1.935, 1.835, 3.220. The first reading was with staff held on benchmark of RL 100.000 m. Enter the readings in a page of level book and calculate the RL of all points. Apply arithmetic checks. Use plane of collimation method.

PLEASE FIND SOLUTION THAT WILL COME UP WITH THE SAME ANSWER The two-peg test is used to determine if the line of sight of an engineer’s level is in adjustment, and the following rod readings are taken: with instrument set up near A, rod reading on A is 1.623 m, rod reading on B is 2.875 m; with instrument set up near B, rod reading on B is 1.622 m, and rod reading on A is 0.362 m.   i. The correct rod reading on A to give a level line of sight with the instrument still set up near B should be? answer: 0.366 m ii. In order to adjust the line of sight, the horizontal cross hairs should be moved? answer: Upward by 0.004 m

b) Table Q2(b) shows booking of a two-peg test. i). Calculate the reduced levels of point B ii). Calculate the collimation error after the two-peg test Table Q2(b). Two-peg test booking BS FS Height of Collimation (m) Reduced Level (m) Remark Distance, L = 60 m (Set 1) 1.653 10.000 A 1.322 1.406 В 1.567 A Distance, L = 60 m (Set 2) 1.614 1.498 1.366 10.000 A B A 1.742