The reaction shown below yields one major addition product as a racemic mixture. + >XT Cl₂ For the mechanism step below, draw curved arrows to show electron reorganization. Consider the formation of just one of the product stereoisomer Arrow-pushing Instructions H₂O CH3SOCH3 (DMSO) :CI:
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- Draw the structure of the alkene with the molecular formula CH10 that reacts with Br, to give this compound. CH3 Br Br • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. opyste ot pt pt pt ptDraw a structural formula for the substitution product of the reaction shown below. H/ ● (CH3)3C |YY Br ΔΟ H Na • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If more than one stereoisomer of product is formed, draw both. Separate multiple products using the + sign from the drop-down menu. • Products that are initially formed as ions should be drawn in their neutral forms. SH acetone [FQUESTI ON 3 Use Hammond's postulate to determine which alkene in each pair would be expected to form a carbocation faster in an electrophilic addition reaction. Choose the more reactive compound for both pairs. Two answers will be required. or or || IV II IV O000
- Draw the structural formula of the product of the reaction shown below. + H₂O AAVIL H₂SO4 • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If the reaction produces a racemic mixture, just draw one stereoisomer. Sn [F Ⓡ ChemDoodleDraw the organic product of the following reaction. CH3 m-CICgH,CO;H • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If the reaction produces a racemic mixture, just draw one stereoisomer. • If more than one product is possible, only draw the major product. opy asteShown below is a carbocation intermediate in an electrophilic addition reaction of HCl with an alkene. For the conformation shown, select each hydrogen whose bond to carbon is aligned for effective hyperconjugation with the vacant p orbital on the positively charged carbon. Each adjacent carbon will have only one C-H bond so aligned. • Gray = C; white = H; red = 0; blue = N; dark green = Cl; brown =Br; light green =F; purple = I; yellow = S; orange = P. • Double click to select atoms. • You can zoom in and out using the mouse scroll wheel (or pinch to zoom on touch screens).
- Draw the bond-line (skeletal) structure of the compound with molecular formula C₂H₁3Br that gives the following alkene as the exclusive product of E2 elimination. Click and drag to start drawing a structure. C X C Ś c+The following reaction is electrophilic substitution: 3- [Pt(CH₂) (N) [Pt(CH3)(CI) (PMePh₂)₂] + N° (PMePh₂)₂] + CI Select one: O True O FalseThe two alkenes below react with HI at different rates. CH3CH=CHCH3 and CH₂=CH₂ Draw the structural formula of the MAJOR product formed by the alkene having the HIGHER reaction rate. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. TAYY [ ] در ChemDoodle Ⓡ
- Draw a structural formula for the product formed upon hydroboration/oxidation of the alkene below. CH3 OG 1 Use wedge and hash bonds ONLY for rings. Do not show stereochemistry in other cases. • If the reaction produces a racemic mixture, just draw one stereoisomer. ● 981 CH3 ***** // Q Y ? [F BWhat is the predicted product of the reaction shown? O & N(CH3)2 | IV (CH3)2NH H₂SO4 1. N(CH3)2 2. H3O+ || ОН HO |||Draw a structural formula for the substitution product of the reaction shown below. ● H3C HH Br + O • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If more than one stereoisomer of product is formed, draw both. Separate multiple products using the + sign from the drop-down menu. • Products that are initially formed as ions should be drawn in their neutral forms. ▼ In [F OCH 3 -85 ? Na CN CH3CH₂OH ChemDoodleⓇ >