
The reaction of divalent manganese with oxygen in aqueous solution is given as follows:
Mn2+ + 1/2O2(aq) + H2O = MnO2(s) + 2H+
The equilibrium constant (K) for this reaction is 23.7. It has been found that a lake water sample that contains no oxygen at 25 C, pH = 8.5, originally contained 0.6 mg/L of Mn2+. The sample was aerated (atmospheric conditions of the dissolved oxyen concentration is 9.2 mg/L) and after 10 days of contact with atmospheric oxygen, the Mn2+ concentration was 0.4 mg/L. The molecular weight of Mn is 55, O is 16 and H is 1. The change in free energy of formation at standard conditions (kcal/mole) are as follows: Mn2+ = -54.4, O2(aq) = +3.93, H2O = -56.69, MnO2(s) = -111.1, H+ = 0.
(a) Assuming that the pH remains constant during aeration, will the precipitate continue to form after the measurement on the tenth day?
(b) What should the Mn2+ concentration be (in moles/L) at equilibrium, assuming that pH and presence of dissolved oxygen are the same as in part "a". Assume ideal conditions

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