The reaction of 1.0 gram of aluminum (Al) and 1.0 gram of oxygen (O2) according to the reaction below produced 1.7 grams of aluminum oxide (Al2O3). 4 Al (s) + 3 O2 (g) → 2 Al2O3 (s) Calculate the percent yield of aluminum oxide
The reaction of 1.0 gram of aluminum (Al) and 1.0 gram of oxygen (O2) according to the reaction below produced 1.7 grams of aluminum oxide (Al2O3). 4 Al (s) + 3 O2 (g) → 2 Al2O3 (s) Calculate the percent yield of aluminum oxide
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The reaction of 1.0 gram of aluminum (Al) and 1.0 gram of oxygen (O2) according to the reaction below produced 1.7 grams of aluminum oxide (Al2O3).
4 Al (s) + 3 O2 (g) → 2 Al2O3 (s)
Calculate the percent yield of aluminum oxide
Expert Solution
Step 1
Since from the given reaction we can see that 4 mole of Al will need 3 moles of O2 to react completely
And moles of Al taken = mass / Atomic mass = 1 / 27 = 0.03704
And moles of O2 taken = mass / molar mass = 1 / 32 = 0.03125
Hence moles of O2 required for completely reacting with 0.03704 moles of Al = moles of Al X 3 / 4 = 0.03704 X 3 / 4 = 0.0278 approx
Since moles of O2 required is less than the taken
Hence Limiting reagent will be Al
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