Answered: The radius of Jupiter is about 68.0 ×…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 58P

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The radius of Jupiter is about 68.0 × 10³ km. The radius of the Earth is about 6300.0 km. How many Earth volumes would fit inside Jupiter's volume?

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Expert Solution

Step 1

Given data

The radius of Jupiter is $R_{J} = 68.0 \times 10^{3} km$

The radius of Earth is $R_{E} = 6300 km$

The volume of Jupiter is,

$\begin{array}{rcl} V_{J} & = & \frac{4}{3} π {(R_{J})}^{3} \\ = & \frac{4}{3} π {(68.0 \times 10^{6} m)}^{3} \\ = & 1.317 \times 10^{24} m^{3} \end{array}$

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