the question below is already answered in the photos that I provided I only want to ask how did it find the answers Saturated steam at a pressure of 25 psia is sprayed into a stream of moist air. The initial condition of the air is 55 dry-bulb temperature and 35 F de-point temperature. The mass rate of air

Elements Of Electromagnetics
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the question below is already answered in the photos that I provided I only want to ask how did it find the answers

Saturated steam at a pressure of 25 psia is sprayed into a stream of moist air. The initial condition of the air is 55 dry-bulb temperature and 35 F de-point temperature. The mass rate of air flow is 2000 lb per min. Barometric pressure is 14.696 psia. Determine how much steam must be added in lb per min to produce a saturated air condition, b) the resulting temperature of the saturated air.

my question here is:
regarding of the solution pls elaborate how did it get w1 and h1 is it given in the psychrometric chart or it has a specific solution to follow

From Paychmometric chent
at stufe ♡ →
W, = 0-004
hi = 18-01 BTU B of day aite
We = 0-101 , hz = 23 Bru lomgf dhay ain
->
at stafe @ →
a) amomt Stemodded min → ms = m(We-W.)
of
ms = & om (0- l01-0•004)
轉194 4iy
) :: Q = m[ he-hi] = 200x [23-18-01] - 9980 bru/mig
9980=Q000 X02yx [TF-ss]
%D
TF=75.8°F
Transcribed Image Text:From Paychmometric chent at stufe ♡ → W, = 0-004 hi = 18-01 BTU B of day aite We = 0-101 , hz = 23 Bru lomgf dhay ain -> at stafe @ → a) amomt Stemodded min → ms = m(We-W.) of ms = & om (0- l01-0•004) 轉194 4iy ) :: Q = m[ he-hi] = 200x [23-18-01] - 9980 bru/mig 9980=Q000 X02yx [TF-ss] %D TF=75.8°F
Guen - →
stak@→ DBT, = ss'F
DPT, = 35F
mes tlow ote (m) = 2oolbomlmin
initiap condition
state ♡→ Find state
Satneked cir → DBT2 =5 SF, RH2=(0.
Transcribed Image Text:Guen - → stak@→ DBT, = ss'F DPT, = 35F mes tlow ote (m) = 2oolbomlmin initiap condition state ♡→ Find state Satneked cir → DBT2 =5 SF, RH2=(0.
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