The proprietor of a greenhouse claims that its pots of lilies average 6.0 buds, with s = 0.4 buds. If n = 29 pots of lilies from a large no of pots of lilies has a mean of 5.8 buds, does this deny the proprietor’s claim of the mean number of buds at 0.015 level of significance?
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- The proprietor of a greenhouse claims that its pots of lilies average 6.0 buds, with s = 0.4 buds. If n = 29 pots of lilies from a large no of pots of lilies has a
mean of 5.8 buds, does this deny the proprietor’s claim of the mean number of buds at 0.015 level of significance?
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- Consider the trash bag problem. Suppose that an independent laboratory has tested trash bags and has found that no 30-gallon bags that are currently on the market have a mean breaking strength of 50 pounds or more. On the basis of these results, the producer of the new, improved trash bag feels sure that its 30-gallon bag will be the strongest such bag on the market if the new trash bag's mean breaking strength can be shown to be at least 50 pounds. The mean of the sample of 39 trash bag breaking strengths in Table 1.10 is x = 50.573. If we let u denote the mean of the breaking strengths of all possible trash bags of the new type and assume that o equals 1.61: Using the 95 percent confidence interval, can we be 95 percent confident that u is at least 50 pounds?6. A kinesiologist wanted to examine the effects of temperature and humidity on exercise performance. Each participant was asked to walk on a treadmill at a normal pace for 60 minutes, and the kinesiologist recorded the distance walked (miles). She assigned participants to one of 4 conditions that varied in temperature (normal or high) and humidity (normal or high). Mean distance walked by the four groups are shown in the table below. Assume a = .05 and Tukey HSD = 0.39. Normal temperature High temperature Normal humidity M = 3.00 M = 2.80 High humidity M = 2.80 M = 2.00 Complete the following conclusion: The factorial ANOVA revealed significant main effects of temperature [F (1, 24) = 25.00, p<.05] and humidity [F (1, 24) = 19.65, p<.05] and a significant Temperature x Humidity interaction [F (1, 24) = 9.25, p < .05].A certain type of battery supercharger was found to take a mean of 15.4 minutes to charge a standard electric vehicle (EV) battery. A firmware update for this type of supercharger was recently released, but the update has received negative reviews from users. A researcher suspects the mean time the updated superchargers take to charge a standard EV battery is greater than 15.4 minutes. To test his claim, he chooses 15 of the updated superchargers at random and measures the time it takes each one to charge a standard EV battery. He finds that the superchargers take a sample mean of 16.1 minutes to charge a standard EV battery, with a sample standard deviation of 1.8 minutes. Assume that the population of amounts of time to charge a standard EV battery using the updated superchargers is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that u, the mean time…
- The Management Department recently purchased a smallcopier for faculty use. Although the workload of the office staff has improved somewhat, the secretaries are still mak-ing too many trips to the Dean’s office when the depart-mental copier is out of service. Sylvia, the departmental secretary, has been keeping track of failure rates and ser-vice times. With a mean time between failures of 100 hours and a mean time to repair of 24 hours, how much of thetime is the new copier available for faculty use?. A process that cuts lengths of metal with high precision has historically produced metal rods with length that is normally distributed and with a mean of 800 millimetres (mm). Management at the factory is concerned that after an overhaul of the machine the mean length of the rods being produced could differ from the required 800 mm. If it is found that the rods are not being produced to specifications then the machine will have to be stopped for readjustment, with a consequent loss of production. The production line manager tasked with investigating the issue finds that a (random) sample of 25 rods yielded a mean length of 806 mm and a sample standard deviation of 10 mm. i. The mean of the sample is clearly not the required 800 mm. Say why this is not enough information in itself to say if the machine is operating correctly or not. ii. State the null and alternative hypotheses for this situation.Pavan.88.9
- Last year. the mean number of ladies' bags produced by GB Company was 2500 each day. This year, the manager claims that there an increase in the number of bags produced. A researcher who wants to find out whether this is true counted the number of bags produced each day tor a period of one month. His computation resulted to a mean of 2,515 ladies' bags. At 0.05 significance level, is there enough evidence to concludeude that the mean number of ladies' bags produced by GB Company is greather than 2500? Use the 6 steps of hypothesis testing in answering this problem. α=0.05μ=2500mean= 2515N=30SD=72Monthly salary computations from two different companies yielded the following data: n1 = 7, x1=9,120$, s1=384$; n2 = 7, x2=8,820$, s2=214$. At the level of significance 0.05, can we conclude that the mean monthly salary from the two ompanies is not the same?Consider the trash bag problem. Suppose that an independent laboratory has tested trash bags and has found that no 30-gallon bags that are currently on the market have a mean breaking strength of 50 pounds or more. On the basis of these results, the producer of the new, improved trash bag feels sure that its 30-gallon bag will be the strongest such bag on the market if the new trash bag's mean breaking strength can be shown to be at least 50 pounds. The mean of the sample of 45 trash bag breaking strengths in Table 1.10 is = 50.573. If we let µ denote the mean of the breaking strengths of ail possible trash bags of the new type and assume that o equals 1.66: (a) Calculate 95 percent and 99 percent confidence intervals for u. (Round your answers to 3 decimal places.) OE 95 percent confidence intervals for u is 50.068 51.078 ). 51.192 . 99 percent confidence intervals for u is 49.940 (b) Using the 95 percent confidence interval, can we be 95 percent confident that u is at least 50…
- Example 19.13 A company used three different methods of advertising its product in three cities. It later found the increased sales (in thousand rupees) in identical retail outlets in the three cities as follows: City A: City B: City C: 70 58 60 45 55 62 89 72 65 57 48 55 75 68 45 52 63 53 59 71 70 63 60 58 75Show the 4-Step Method in testing significance of mean difference in the following case:A topic of recent clinical interest is the effect of different contraceptive methods on fertility. Suppose we wish to compare how long it takes users of either oral contraceptives (OCs) or diaphragms to become pregnant after stopping contraception. A study group of 20 OC users is formed, and diaphragm users who match each OC user with regard to age (within 5 years), race, parity (number of previous pregnancies), and socioeconomic status (SES) are found. The investigators compute the differences in time to fertility between previous OC and diaphragm users and find that the mean difference đ (OC minus diaphragm) in time to fertility is 4 months with a standard deviation (sd) of 8 months. Can we conclude that previous OC users take a significantly longer time to become pregnant than do previous diaphragm users?
