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The proportion of left-handed people in the general population is about 0.10.1. Suppose a random sample of 225225 people is observed.
Using our "rule of thumb," can we use normal approximation values for this sampling distribution? Answer
??=np= Answer
and ??=nq= Answer
(Click to view hint)
What is the mean of the sample proportion?
??ˆ=μp^= Answer
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What is the standard error?
??ˆ=σp^= Answer (Click to view hint)
What interval is almost certain (probability 0.9970.997) to contain the sample proportion of left-handed people?
The sample proportion is almost certain to be between Answerand Answer (Click to view hint)
In a sample of 225225 people, would it be unusual to find that 4040 people in the sample are left-handed? Answer (Click to view hint)
Find the approximate probability of at least 3030 in 225225 of being left-handed. What is the sample proportion?
?ˆ=p^= Answer (Round to the nearest hundredth.) (Click to view hint)
Write the problem using probability notation.
?(?ˆP(p^ Answer0.13)0.13)
What is the ?z-score?
?(?ˆ≥0.13)=?(?≥P(p^≥0.13)=P(z≥ Answer )) (Click to view hint)
Which illustration (below) shows the area represented by this probability? Answer
| Curve | Image |
|---|---|
| Curve 1 | |
| Curve 2 | |
| Curve 3 | |
| Curve 4 | |
| Curve 5 |
Find the probability using the normal table (opens in new window).
?(?ˆ≥0.13)=?(?≥1.5)=P(p^≥0.13)=P(z≥1.5)= Answer (Click to hide hint)
The probability is greater than (area to the right), so we need to subtract the area given on the table from 1.
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