The product of the acid-catalyzed epoxide ring-opening reaction below is formed as a racemic mixture. H30* For the mechanism step below, draw curved arrows to show electron reorganization. Consider the formation of just one of the product stereoisomers. Arrow-pushing Instructions + H H H H.

The S 1 mechanism starts with the rate-determining step which is the dissociation of the alkyl halide into a carbocation and a halide ion. The next step is the rapid reaction of the carbocation intermediate with the nucleophile; this step, completes the nucleophilic substitution stage. The step that follows the nucleophilic substitution is a fast acid-base reaction. The nucleophile now acts as a base to remove the proton from the oxonium ion from the previous step, to give the observed product. Draw a curved arrow mechanism for the reaction, adding steps as necessary. Be sure to include all nonzero formal charges. Draw or edit atoms, groups, or bonds Add/Remove step 2 9 Click and drag to start drawing a structure. ale

3) For the 2 elementary steps shown below leading to two possible carbocations A and B, draw mechanism arrows to H. CH3 H-Br: | CH3 show how the SM is converted to each product. Label the reaction coordinate diagram below corresponding to these elementary steps with SM, A, and B and label axes. SM A CH3 CH3 Н-Br: Briefly explain why one carbocation intermediate is higher in energy than the other (structural answers, few words). SM TH. В Are these reactions in #3 endothermic or exothermic? (circle one) Why (brief, one phrase answer):

3. Show a plausible mechanism for the reaction below. , NH2 ELOH, cat. HCI CH H,C- CH NH, CH

Me MeOH Ме Me Ме Me Me -Br Br (RDS) H' Et \'H Et Et H Et A Br Me Ме + en HBr H' Et 1. Complete the mechanism above by filling in curved arrows to depict electron flow. Is the MeOH nucleophile involved in the RDS (rate determining step)?

2. For each reaction, say what is the expected Mechanism, Sn1 or Sn2, and say if the product is optically active (rotate a plane of polarized light), Yes or No, and briefly explain your answers? NaOH H₂O + Br ů NaOCH 3 CH₂OH OH ỌCH3 + Nal + NaBr Tam! Mechanism_ Optically Active(Y/N)? Explain? Mechanism Optically Active(Y/N)? Explain?

Thx for the help

The epoxide shown below can form two different products depending on which reaction condition is used. What are the products of each of these reactions? BRIEFLY explain why you get different products depending on the reaction conditions. By far, the easiest way to do this is to show the mechanism for the key step in each reaction and clearly explain this step. HCH₂CH3 CH3 D н’ CH3OH