The probability mass function of a random variable X is given by 1 2 X f(x)=P(X=x) F(x)=P(X ≤ x) a) f(2)=P(X=2) = b) E(X)= c) Var(X) = 0 0.3 0.1 ? 3 0.2 d) Fill F(0), F(1), F(2), F(3) and F(4) in the third row of the above table. e) The conditional probability P(X=4 | X23) = f) The conditional probability P(X=4 | X=3) = g) The conditional probability P(X23 | X=4) = 4 0.3
The probability mass function of a random variable X is given by 1 2 X f(x)=P(X=x) F(x)=P(X ≤ x) a) f(2)=P(X=2) = b) E(X)= c) Var(X) = 0 0.3 0.1 ? 3 0.2 d) Fill F(0), F(1), F(2), F(3) and F(4) in the third row of the above table. e) The conditional probability P(X=4 | X23) = f) The conditional probability P(X=4 | X=3) = g) The conditional probability P(X23 | X=4) = 4 0.3
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Part G
Transcribed Image Text:The probability mass function of a random variable X is given by
1
X
f(x) = P(X=x)
F(x) = P(X ≤ x)
0
0.3
0.1
2
?
3
0.2
a) f(2)=P(X=2) =
b) E(X)=
c) Var(X) =
d) Fill F(0), F(1), F(2), F(3) and F(4) in the third row of the above table.
e) The conditional probability P(X=4 | X23) =
f) The conditional probability P(X=4 | X=3) =
g) The conditional probability P(X>3 | X=4) =
0.3
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