The probability mass function of a random variable X is given by 1 2 X f(x)=P(X=x) F(x)=P(X ≤ x) a) f(2)=P(X=2) = b) E(X)= c) Var(X) = 0 0.3 0.1 ? 3 0.2 d) Fill F(0), F(1), F(2), F(3) and F(4) in the third row of the above table. e) The conditional probability P(X=4 | X23) = f) The conditional probability P(X=4 | X=3) = g) The conditional probability P(X23 | X=4) = 4 0.3

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...