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The principal part of f(x) = x + x²-³√x²+x²¹ for x>0+ (with respect to y(x) = x) is: a) x + x³ b)x³ e) -24/3 d) a how I solved it, Let me know if it's correct, if not let me know why n+x²– (x³ +nª) ¹³ ⇒n+x²-x[|+ ½ x) ⇒n+2³_n-12² 2³-1² so we choose the one with the smallest degree so C.

The principal part of f(x) = x + x²-³√x²+x²¹ for x>0+ (with respect to y(x) = x) is: a) x + x³ b)x³ e) -24/3 d) a how I solved it, Let me know if it's correct, if not let me know why n+x²– (x³ +nª) ¹³ ⇒n+x²-x[|+ ½ x) ⇒n+2³_n-12² 2³-1² so we choose the one with the smallest degree so C.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Let me know if my thinking process and computations are correct and if not let me know why please
The principal part of f(x)=x+x²-√₂²+x" for x->0+ (with respect to up(x) = x) is: a) x + x³ b)x³ e)-4/3 d) a how I solved it, Let me know if it's correct, if not let me know why 2+x²³ - (x³ +2²)¹³ »n+x²-x[|+ __ x) ⇒n+2³_n-12² ⇒2³-1/² 23. so we choose the one with the smallest degree So C.
Transcribed Image Text:The principal part of f(x)=x+x²-√₂²+x" for x->0+ (with respect to up(x) = x) is: a) x + x³ b)x³ e)-4/3 d) a how I solved it, Let me know if it's correct, if not let me know why 2+x²³ - (x³ +2²)¹³ »n+x²-x[|+ __ x) ⇒n+2³_n-12² ⇒2³-1/² 23. so we choose the one with the smallest degree So C.
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