College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A particle's velocity is given by vlt) = -atj, where a = 0.725 m/s? is a constant. (a) Describe the particle's motion. In particular, is it speeding up, slowing down, or maintaining constant speed? speeding up slowing down O maintaining constant speed (b) Find the particle's velocity at t- 0, t= 17.5 s, and t- 6.40 min. (Express your answer in vector form.) vy-0 at t-0 m/s at t- 17.5 S m/s at t-6.40 min -278.4 m/sarrow_forwardA particle moves in one dimension, and its position as a function of time is given by x = (2.2 m/s)t + (−3.2 m/s2)t2. (a) What is the particle's average velocity (in m/s) from t = 0.45 s to t = 0.55 s? (Indicate the direction with the sign of your answer.) Average velocity is the change in position over change in time. Think about how to use the function to find the change in position. m/s (b) What is the particle's average velocity (in m/s) from t = 0.49 s to t = 0.51 s? (Indicate the direction with the sign of your answer.) m/sarrow_forwardA particle moves in one dimension, and its position as a function of time is given by x = (2.1 m/s)t + (−3.0 m/s2)t2. (a) What is the particle's average velocity from t = 0.45 s to t = 0.55 s? (Indicate the direction with the sign of your answer.)(b) What is the particle's average velocity from t = 0.49 s to t = 0.51 s? (Indicate the direction with the sign of your answer.)arrow_forward
- A brick is dropped from the roof of a tall building. After it has been falling for a few seconds, it falls 41.0 mm in a 1.00-ss time interval.What distance will it fall during the next 1.00 s? Ignore air resistance.arrow_forwardThe position of a particle moving along the x axis depends on the time according to the equation x = ct - btº, where x is in meters and t in seconds. Let c and b have numerical values 2.5 m/s4 and 1.2 m/s³, respectively. From t = 0.0 s tot = 2.5 s, Find its velocity at times (b) 1.O s, (c) 2.0 s, (d) 3.0 s, and (e) 4.0 s. Find its acceleration at (i) 4.0 s.arrow_forwardFor the following motion equation s=2t^3 -15t^2+36t-22, t ⩾ 0 a. Find the average velocity and the average acceleration from t=2 to t=4arrow_forward
- Please Asaparrow_forwardAn object moves in a plane from position r1=(-1,-2) m to the position r2=(-2,7 m and then to r3=(3,8)m. The time of the motion is t=30s. Find (a) total displacement; (b) distance between the initial and final positions; (c)distance travelled (d)average velocity and average speedarrow_forwardThe function x (t) = -2.1le-1.93t describes the position, in meters, of a particle on the x-axis as a function of time t, in seconds. Find the particle's velocity at time t = 3.05 s.arrow_forward
- The position of a particle moving along the x axis varies in time according to the expression x = 6t 2, where x is in meters and t is in seconds. Evaluate its position at the following times. (a) t = 2.40 s (b) t = 2.40s + At Xf = (c) Evaluate the limit of Ax/At as At approaches zero to find the velocity at t = 2.40 s. m/sarrow_forwardThe height (feet) of an object moving vertically is given by s = - 16t + 208t + 156, where t is in seconds. Find the object's velocity at t= 5, its maximum height and when it occurs, and its velocity when s = 0.arrow_forwardThe position of a particle moving along the x axis is given in centimeters by x = 9.88 + 1.40 t3, where t is in seconds. Calculate (a) the average velocity during the time interval t = 2.00 s to t = 3.00 s; (b) the instantaneous velocity at t = 2.00 s; (c) the instantaneous velocity at t = 3.00 s; (d) the instantaneous velocity at t = 2.50 s; and (e) the instantaneous velocity when the particle is midway between its positions at t = 2.00 s and t = 3.00 s.arrow_forward
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