The position of a particle moving along the x-axis is given by s(t)=(5.8 m) -(3.06 m/s)t. What ist he displacement (in m) of the particle between 3.00 s and t=6.00 s?

The position of a particle moving along an x axis is given by x = 12.0t2 - 2.00t°, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 3.00 s. (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (f) What is the maximum positive velocity reached by the particle and (g) at what time is it reached? (h) VWhat is the acceleration of the particle at the instant the particle is not moving (other than at t = 0)? (i) Determine the average velocity of the particle between t = 0 and t 3.00 s. (a) Number i Units (b) Number Units (c) Number i Units (d) Number Units (e) Number Units (f) Number Units (g) Number i Units (h) Number i Units (i) Number i Units

A particle moves along the x-axis according to the equation x = 2.00 +3.00t -1.00t^2, where x is in meters and t is in seconds. At t = 3.00s , find the acceleration of the particle.

A particle leaves the origin with an initial velocity 3.00î m/s and a constant acceleration ở -1.00î – 0.50ĵ m/s². When it reaches its maximum x coordinate, what are its (a) velocity and (b) position vector?