The position of a particle as a function of time is given by x=(-2.00 m/s)t + (3.00 m/s³)t³ Part B Find the average velocity of the particle from t = 0.150 s to t= 0.250 s. Vav= Submit Part C 17 ΑΣΦ Vav= Request Answer Find the average velocity from t = 0.190s to t= 0.210s. ? ΕΙ ΑΣΦΑ ? m/s m/s
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- An object's position as a func of time is given by ; x(t) = - 200 (( t + 1 ) ^ - 1) + 6t^2. (Assume constants have proper SI Units) An object's instantaneous velocity at t = 3.00 seconds is 45.5 m/s What is the object's average velocity between t = 0 and t = 3.00 seconds? Answer is 68.0 m/s^2 What is the object's average acceleration between t = 0 and t = 3.00 s Answer : - 50.5 m/s^2An object's position in the as a function of time obeys the equation; x (t) = 3t – 2t³ + 1.5t where all constants have proper SI Units. What is the speed of the object in the x direction at t = 1.75 seconds?A ball is thrown into the air by a baby alien on a planet in thesystem of Alpha Centauri with a velocity of 49 ft/s. Its heightin feet after t seconds is given by y = 49t −25t2.a.) Find the average velocity for the time period beginningwhen t0 = 1 second and lasting for the given time.t = .01 sec:t = .005 sec:t = .002 sec :t = .001 sec: b.) Estimate the instanteneous velocity when t = 1.
- The displacement of a particle is given by s = 3t3 - 42t2 + 109t - 39 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 11 seconds of motion. After you have made the plots, answer the questions. Questions: Att = 2.4 ft. v= ft/sec. a = ft/sec? sec, Att= 5.4 i ft, v= i ft/sec, a = i ft/sec? S= sec, Att = 8.5 ft. v= i ft/sec, a = i ft/sec? sec, The velocity is zero when t = i sec and when t = i secA student drives 1.91 km due west to get coffee before class. The trip to get coffee takes her 7.00 minutes. She then drives 9.37 km at an angle 26.4° south of east to get to campus. The trip from the coffee shop to campus takes her 12.0 minutes. Let the positive r-direction point due east and the positive y-direction point due north. a) Which vector below represents the students average velocity? B. E OĀThe equation of motion of a particle is s= t^3-3t , where is in meters and t is in seconds . (Assume t >_ 0 ) A) find the velocity and acceleration as functions of t . V(t) = V(t)= Find the acceleration after 4s . ____ m/s^2. Find the acceleration when the velocity is 0 ____ m/s^2
- The acceleration of an object (in m/s2) is given by the function a(t)=8sin(t)a(t)=8sin(t). The initial velocity of the object is v(0)=−10v(0)=-10 m/s. Round your answers to four decimal places.a) Find an equation v(t) for the object velocity.v(t)v(t) = −8cos(t)−2Correct b) Find the object's displacement (in meters) from time 0 to time 3.3.4187Incorrect metersc) Find the total distance traveled by the object from time 0 to time 3. meters1039. A car accelerates for t sec from rest to a velocity of 48 ft per sec, the accelera- tion increasing uniformly from zero to 12 ft per sec?. During the next 4 sec, the car decelerates at a constant rate to a velocity of 4 ft per sec. Sketch the a-t, v-t, and 8-t curves.-L.1971+38.67 Time (in seconds) The driver of a vehicle applies the brakes, softly at first, then harder, coming to a complete stop after 7 sec. The velocity as a function of time is modeled by the function v(t) = -1.197t² + 58.67,. where v is in feet per second, t is in seconds and 0sis 7. How far did the vehicle travel while the driver was braking? Velocity (in feet per second)
- The velocity of a particle moving along the x-axis is given by: v ( t) = 4t – 3t?, where v is in cm/s & t in s. | a) What are the dimensions associated with the 4? | b) What are the units associated with the -3? | c) Find an expression for the average acceleration (aav= Av/At) in the time interval t to t + 0.02 s. Simplify your final answer.The displacement of a particle is given by s = 4t3 - 60t² + 100t - 58 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 13 seconds of motion. After you have made the plots, answer the questions. Questions: At t = 1.8 S= i 49.072 ft,v= -77.12 ft/sec, a = -76.8 ft/sec sec, At t = 6.6 S= i 19263.104 ft,v= -169.28 ft/sec, a = 38.4 ft/sec sec, Att = 9.8 S = -1075.632 V = ft/sec,a 115.2 ft/sec sec, The velocity is zero when t = i 217.9795 ft, Mi 10218.304 sec and when t = i 22.0205 secThe displacement of a particle is given by s= 5t³ - 59t² + 87t-68 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 9 seconds of motion. After you have made the plots, answer the questions. Questions: Att = 0.9 S= i ft, v = ft/sec, a = ft/sec² sec, Att = 5 sec, S= ft, v= ft/sec² ft/sec, a = Att = 6.6 sec, i S= ft, v = ft/sec, a = ft/sec² The velocity is zero when t = i Mi i sec and when t = i i sec