MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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The population
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$$We can estimate with 68% confidence that the true value of the population mean is between and
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- A&B&C&Darrow_forwardK A R Explain how finding a confidence interval for a population variance is different from finding a confidence interval for a population mean or proportion. Choose the correct answer below. OA. Unlike a confidence interval for a population variance, a confidence interval for a population mean or proportion does not have a margin or error. The left and right endpoints must be calculated separately. OB. Unlike a confidence interval for a population variance, a confidence interval for a population mean or proportion does not have a margin or error. The left and right endpoints must not be calculated separately OC. Unlike a confidence interval for a population mean or proportion, a confidence interval for a population variance does not have a margin or error. The left and right endpoints must not be calculated separately OD. Unlike a confidence interval for a population mean or proportion, a confidence interval for a population variance does not have a margin or error. The left and right…arrow_forwardYou are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $125.00. Assume the population standard deviation is $19.30 Construct a 90% confidence interval for the population mean. The 90% confidence interval is___________________________. (Round to two decimal places as needed.)arrow_forward
- If we find a 95% confidence interval using a sample, then we can say... 95% of individuals will fall on that interval there is a 5% chance the population proportion is NOT on the interval. 95% of our samples will fall on that interval. No answer text provided.arrow_forwardYou are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of $142.00. Assume the population standard deviation is $18.80. Construct a 90% confidence interval for the population mean. The 90% confidence interval is (____, ____) (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean. The 95% confidence interval is (____, ____) (Round to two decimal places as needed.)arrow_forwardIn a survey, 23 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $47 and standard deviation of $9. Construct a confidence interval at a 80% confidence level.Give your answers to one decimal place.________ ± ________Interpret your confidence interval in the context of this problem.arrow_forward
- Out of 400 people sampled, 224 had children under the age of 18. Based on this, construct a 90% confidence interval for the true population proportion of people with children under the age of 18.Give your answers as decimals, to three places.________< p <________arrow_forwardTina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.arrow_forwardWhich one of the following statements is true? The sample proportion is a parameter. A confidence interval is computed in order to estimate an unknown sample statistic. The margin of error is affected by the size of the sample proportion. If you construct a confidence interval for a population proportion and the interval ends up being from 0.48 to 0.59, this means the population proportion is definitely larger than 0.50. If a 95% confidence interval is given as 0.32 to 0.46, this means the sample proportion must be 0.38.arrow_forward
- You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 50 home theater systems has a mean price of $118.00. Assume the population standard deviation is $19.60. Construct a 90% confidence interval for the population mean. The 90% confidence interval is ( ). (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean. The 95% confidence interval is ( ,). (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. O A. With 90% confidence, it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population mean price lies in the second interval. The 95% confidence interval is wider…arrow_forwardYou are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 40 home theater systems has a mean price of $117.00.Assume the population standard deviation is $18.40.arrow_forwardUse the given data to construct a confidence interval for the population proportion p of the requested level. x = 52, n = 71, confidence level 95% Round the answer to at least three decimal places. D. The confidence interval isarrow_forward
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