The polarizers are rotated so that the second polarizer has a transmission of 36.2° with respect to the first polarizer and the third polarizer has an angle of 90.0° with respect to the first. If I, is the intensity of the original unpolarized light, what is the intensity of the beam at the following times. (a) after it passing through the second polarizer 12/1=[ (b) after it passing through the third polarizer 13/16- =
The polarizers are rotated so that the second polarizer has a transmission of 36.2° with respect to the first polarizer and the third polarizer has an angle of 90.0° with respect to the first. If I, is the intensity of the original unpolarized light, what is the intensity of the beam at the following times. (a) after it passing through the second polarizer 12/1=[ (b) after it passing through the third polarizer 13/16- =
Transcribed Image Text:PROBLEM Unpolarized light is incident upon three polarizers. The first polarizer has a vertical
transmission axis, the second has a transmission axis rotated 30.0° with respect to the first, and the third
has a transmission axis rotated 75.0° relative to the first. If the initial light intensity of the beam is I
calculate the light intensity after the beam passes through (a) the second polarizer and (b) the third
polarizer.
STRATEGY After the beam passes through the first polarizer, it is polarized and its intensity is cut in
half. Malus's law can then be applied to the second and third polarizers. The angle used in Malus's law
must be relative to the immediately preceding transmission axis.
SOLUTION
(A) Calculate the intensity of the beam after it passes through the second polarizer.
The incident intensity is 1/2. Apply
Malus's law to the second polarizer.
2
12 = 10 cos²0=cos² 30º =((32") ² = 3/8 1
2
(B) Calculate the intensity of the beam after it passes through the third polarizer.
The incident intensity is now 31,/8.
31,
2
13=12 cos²0=31cos² 45⁰ m²
3/4 ((2) ²)² = 3/16 1
Apply Malus's law to the third polarizer.
8
LEARN MORE
REMARKS Notice that the angle used in part (b) was not 75.0°, but 75.0° -30.0° = 45.0°. The angle is
always with respect to the previous polarizer's transmission axis because the polarizing material physically
determines what direction the transmitted electric fields can have.
QUESTION At what angle relative to the previous polarizer must an additional polarizer be placed so as
to completely block the light?
EXERCISE
HINTS: GETTING STARTED | I'M STUCK!
The polarizers are rotated so that the second polarizer has a transmission of 36.2° with respect to the first
polarizer and the third polarizer has an angle of 90.0° with respect to the first. If I, is the intensity of the
original unpolarized light, what is the intensity of the beam at the following times.
(a) after it passing through the second polarizer
1₂/16 -|
(b) after it passing through the third polarizer
13/1²
What is the final transmitted intensity if the second polarizer is removed?
1/1₂ =
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