The point x = 0 is a regular singular point of the given differential equation. Find the recursive relation for the series solution of the DE below. Show the substitution and all the steps to obtain the recursive relation. Do not solve the equation for y=y(x) xy" + 4y'- xy = 0, a. Cx+1= b. Ck+1= C. CK = d. Ck = e. Ck= 1 (k+r+ 1)(k+r+3) 1 (k+r+ 1)(k+r+4) Ck-1, k≥1 1 k+r k+r ·Ck-1, k≥1 -Ck-1, k≥1 -Ck-1, k≥1 (k+r)² +5(k+r) 1 (k+r)²-2(k+r) -8 ·CK-2, k≥2

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Title: Recursive Relation for Series Solution of a Differential Equation**

**Problem Statement:**
The point \( x = 0 \) is a regular singular point of the given differential equation. **Find the recursive relation for the series solution of the differential equation (DE) below.** Show the substitution and all steps to obtain the recursive relation. **Do not solve the equation for \( y = y(x) \).**

**Differential Equation:**
\[ xy'' + 4y' - xy = 0, \]

**Potential Recursive Relations:**

a. \( c_{k+1} = \frac{1}{(k + r + 1)(k + r + 3)}c_{k-1}, \quad k \geq 1 \)

b. \( c_{k+1} = \frac{1}{(k + r + 1)(k + r + 4)}c_{k-1}, \quad k \geq 1 \)

c. \( c_k = \frac{1}{k + r}c_{k-1}, \quad k \geq 1 \)

d. \( c_k = -\frac{k + r}{(k + r)^2 + 5(k + r)}c_{k-1}, \quad k \geq 1 \)

e. \( c_k = -\frac{1}{(k + r)^2 - 2(k + r) - 8}c_{k-2}, \quad k \geq 2 \)

**Explanation:**
This exercise involves verifying which option provides the correct recursive relation for the coefficients \( c_k \) in the series solution to the differential equation. To solve it, you would typically:

1. Assume a power series solution \( y = \sum_{k=0}^{\infty} c_k x^{k+r} \).
2. Substitute this into the differential equation: \[ x \sum_{k=0}^{\infty} (k+r)(k+r-1)c_k x^{k+r-2} + 4 \sum_{k=0}^{\infty} (k+r)c_k x^{k+r-1} - x \sum_{k=0}^{\infty} c_k x^{k+r} = 0. \]
3. Combine and simplify the series terms.
4. Obtain a recurrence relation
Transcribed Image Text:**Title: Recursive Relation for Series Solution of a Differential Equation** **Problem Statement:** The point \( x = 0 \) is a regular singular point of the given differential equation. **Find the recursive relation for the series solution of the differential equation (DE) below.** Show the substitution and all steps to obtain the recursive relation. **Do not solve the equation for \( y = y(x) \).** **Differential Equation:** \[ xy'' + 4y' - xy = 0, \] **Potential Recursive Relations:** a. \( c_{k+1} = \frac{1}{(k + r + 1)(k + r + 3)}c_{k-1}, \quad k \geq 1 \) b. \( c_{k+1} = \frac{1}{(k + r + 1)(k + r + 4)}c_{k-1}, \quad k \geq 1 \) c. \( c_k = \frac{1}{k + r}c_{k-1}, \quad k \geq 1 \) d. \( c_k = -\frac{k + r}{(k + r)^2 + 5(k + r)}c_{k-1}, \quad k \geq 1 \) e. \( c_k = -\frac{1}{(k + r)^2 - 2(k + r) - 8}c_{k-2}, \quad k \geq 2 \) **Explanation:** This exercise involves verifying which option provides the correct recursive relation for the coefficients \( c_k \) in the series solution to the differential equation. To solve it, you would typically: 1. Assume a power series solution \( y = \sum_{k=0}^{\infty} c_k x^{k+r} \). 2. Substitute this into the differential equation: \[ x \sum_{k=0}^{\infty} (k+r)(k+r-1)c_k x^{k+r-2} + 4 \sum_{k=0}^{\infty} (k+r)c_k x^{k+r-1} - x \sum_{k=0}^{\infty} c_k x^{k+r} = 0. \] 3. Combine and simplify the series terms. 4. Obtain a recurrence relation
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