The personnel director of a large hospital is interested in determining the relationship (if any) between an employee's age and the number of sick days the employee takes per year. The director randomly selects ten employees and records their age and the number of sick days which they took in the previous year. Employee 1 2 3 4 5 30 50 40 55 3 Age Sick Days 7 4 2 9 Copy Data The estimated regression line and the standard error are given. 7 8 9 10 25 30 45 8 5 2 6 30 28 60 10 0 Sick Days = 14.310162 – 0.2369(Age) Se= 1.682207 Find the 99 % confidence interval for the average number of sick days an employee will take per year, given the employee is 49. Round your answer to two decimal places.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
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Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
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The personnel director of a large hospital is interested in determining the relationship (if any) between an employee's age and the number of sick days the employee
takes per year. The director randomly selects ten employees and records their age and the number of sick days which they took in the previous year.
Employee
Age
Sick Days
1 2 3 4 5 6 7 8 9 10
30 50 40 55 30 28 60 25 30 45
7 4 3 2 9 10 0
5 2
8
Copy Data
The estimated regression line and the standard error are given.
Sick Days = 14.310162 - 0.2369(Age)
Se 1.682207
Find the 99 % confidence interval for the average number of sick days an employee will take per year, given the employee is 49. Round your answer to two decimal
places.
Transcribed Image Text:The personnel director of a large hospital is interested in determining the relationship (if any) between an employee's age and the number of sick days the employee takes per year. The director randomly selects ten employees and records their age and the number of sick days which they took in the previous year. Employee Age Sick Days 1 2 3 4 5 6 7 8 9 10 30 50 40 55 30 28 60 25 30 45 7 4 3 2 9 10 0 5 2 8 Copy Data The estimated regression line and the standard error are given. Sick Days = 14.310162 - 0.2369(Age) Se 1.682207 Find the 99 % confidence interval for the average number of sick days an employee will take per year, given the employee is 49. Round your answer to two decimal places.
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