The orthorhombic unit cell of NiSO4 has the dimensions a= 634 pm, b = 784 pm, and c = 516 pm, and the density of the solid is estimated as 3.9 g cm-3. Determine the number of formula units per unit cell and calculate a moreprecise value of the density.

The orthorhombic unit cell of NiSO4 has the dimensions a= 634 pm, b = 784 pm, and c = 516 pm, and the density of the solid is estimated as 3.9 g cm-3. Determine the number of formula units per unit cell and calculate a moreprecise value of the density.

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter21: Structure And Bonding In Solids

Section: Chapter Questions

Problem 25P

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Concept explainers

Crystal Lattices and Unit Cell

Consider a crystal. The regular and repeating pattern of constituent particles is the most distinguishing feature of crystalline solids. A crystal lattice is formed when these particles are replaced with representative points. The three-dimensional arrangement of constituent particles is known as a crystal lattice. Unit cell is that the smallest portion of a space lattice which when repeated in several directions, generate the whole lattice. Unit cell is a building block of a lattice. It is the smallest unit of cell.

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The orthorhombic unit cell of NiSO₄ has the dimensions a= 634 pm, b = 784 pm, and c = 516 pm, and the density of the solid is estimated as 3.9 g cm^-3. Determine the number of formula units per unit cell and calculate a more
precise value of the density.

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