The original charge of a parallel plate capacitor is 144 mC on each plate. After a dielectric is put between the charge changes to 400 mC. What is dielectric constant?

The volume enclosed by the plates of a parallel plate capacitor is given by the equation Volume = Ad. If one doubles the area, A, of the plates and reduces the plate separation, d, by a factor of two so that the volume remains the same, the capacitance will do which of the following? decrease by a factor of 4 O increase by a factor of 4 increase by a factor of 2 decrease by a factor of 2 O remain constant

Area = A dielectric capacitor plates A parallel plate capacitor has each plate area as 3 cm x 4 cm, separated by a 1.0 mm thick cardboard represented by the purple layer in the figure (dielectric constant € = 3.8), is fully charged. Find the capacitance (C) and the maximum charge (Qmax) on the capacitor if it's charged with an electric field E = 16 x 106 V/m.,

A fully charged parallel plate capacitor has a dielectric between its plates. If the dielectric material is removed, the potential difference across the plates increases by 35 %. What is the dielectric constant of the dielectric? Assume that the capacitor is not connected to a source potential after being fully charged.