The organophosphate nerve agent A-234 is believed to have the formula C5H8F2NO3P. It is one of the lethal chemical compounds known as Novichok agents which poisoned former Russian intelligence officer Sergei Skripal and his daughter Yulia on March 4, 2018 in Salisbury, England. How many fluorine atoms are in 100. micrograms of A-234? (Note: This amount is likely a lethal dose.)

Molecular formula: C₅H₈F₂NO₃P

Isotope of organophosphate nerve agent with molecular formula C₅H₈F₂NO₃P is represented by formula A-234.

Molar Mass of A-234 :

$$\begin{gathered} no. of C\times mass ofeach C+no. of H\times mass ofeach H+no. of F\times mass ofeach F+no. ofeach N\times mass ofeach N+ \\ no. of O\times mass ofeach O+no. of P\times mass ofeach P \end{gathered}$$

= $(5\times 12 +8\times 1+2\times 9+1\times 14+3\times 16+1\times 31) g mo{l}^{-1}$

= 179 g mol^-1

To determine number of fluorine atoms in 100 micrograms of A-234.