The number of bacteria in a flask grows according to the differential equation dy/dt=0.09y In this question, time is measured in hours and the number of bacteria, y, is measured in millions. The number of bacteria at time t = 0 is 15 million. Enter a formula for the number of bacteria at time t y = What is the value of the growth constant? Growth constant : ___ per hour. How long does it take for the number of bacteria to double? (Enter your answer correct to two decimal places.) Doubling time : ___ hours. How many million bacteria will be present after 5 hours have passed? (Enter your answer correct to one decimal place.) Number present after 5 hours : million.
The number of bacteria in a flask grows according to the differential equation dy/dt=0.09y In this question, time is measured in hours and the number of bacteria, y, is measured in millions. The number of bacteria at time t = 0 is 15 million. Enter a formula for the number of bacteria at time t y = What is the value of the growth constant? Growth constant : ___ per hour. How long does it take for the number of bacteria to double? (Enter your answer correct to two decimal places.) Doubling time : ___ hours. How many million bacteria will be present after 5 hours have passed? (Enter your answer correct to one decimal place.) Number present after 5 hours : million.
The number of bacteria in a flask grows according to the differential equation dy/dt=0.09y In this question, time is measured in hours and the number of bacteria, y, is measured in millions. The number of bacteria at time t = 0 is 15 million. Enter a formula for the number of bacteria at time t y = What is the value of the growth constant? Growth constant : ___ per hour. How long does it take for the number of bacteria to double? (Enter your answer correct to two decimal places.) Doubling time : ___ hours. How many million bacteria will be present after 5 hours have passed? (Enter your answer correct to one decimal place.) Number present after 5 hours : million.
The number of bacteria in a flask grows according to the differential equation
dy/dt=0.09y
In this question, time is measured in hours and the number of bacteria, y, is measured in millions.
The number of bacteria at time t = 0 is 15 million.
Enter a formula for the number of bacteria at time t
y =
What is the value of the growth constant?
Growth constant : ___ per hour.
How long does it take for the number of bacteria to double?
(Enter your answer correct to two decimal places.)
Doubling time : ___ hours.
How many million bacteria will be present after 5 hours have passed?
(Enter your answer correct to one decimal place.)
Number present after 5 hours : million.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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