The number density of air in a child's balloon is roughly the same as sea level air, 1019 particles/cm3. If the balloon is now 16 cm in diameter, to what diameter (in km) would it need to expand to make the gas inside have the same number density as the ISM, about 1 particle/cm3?
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The number density of air in a child's balloon is roughly the same as sea level air, 1019 particles/cm3. If the balloon is now 16 cm in diameter, to what diameter (in km) would it need to expand to make the gas inside have the same number density as the ISM, about 1 particle/cm3?
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- Imagine that you have air in a sealed glass container that has a volume of 1 liter. The pressure inside the container is 1013 hPa and the temperature is 20◦C. You now inject cloud droplets into the chamber without letting any air leak out. The droplets have a radius of 10 micrometers, and you inject a concentration of drops that is typical of what you find in a cloud (200 drops per cm3). Will there be a change in the gas pressure? If so, by what amount? Please provide a calculation. What does your answer tell you about the presence of particles in the atmosphere and their potential influence on pressure?Atmospheric pressure on Earth at its surface is 101 KPa (101 kilopascals or 101,000 N/m2). Which of these statements is true. When we reduce the pressure in the container while keeping the temperature constant, the number of atoms per m3 must stay constant. At 1 atmosphere, the number of atoms/m3 in air at room temperature is about 109, one billion atoms. If we pump out the gas in a closed container leaving only 1 billionth of the original gas there will be fewer than 100 atoms per m3 in the container. If we pump out the gas in a closed container leaving only 1 billionth of the original gas there will still be more than 1010 (10 billion) atoms per cm3 in the container.Ideal gases are often studied at standard ambient temperature and pressure (SATP). The International Union of Pure and Applied Chemistry (IUPAC) defines SATP to be T = 25° C and P = 100 kPa. a. Calculate N/V (in particles per cubic meter) for an ideal gas at SATP b. How many atoms of an ideal gas at SATP are there in one cubic centimeter?
- Atmospheric pressure on Earth at its surface is 101 KPa (101 kilopascals or 101,000 N/m2). Which of these statements is true? If we pump out the gas in a closed container leaving only 1 billionth of the original gas there will still be more than 1010 (10 billion) atoms per cm3 in the container. If we pump out the gas in a closed container leaving only 1 billionth of the original gas there will be fewer than 100 atoms per m3 in the container. When we reduce the pressure in the container while keeping the temperature constant, the number of atoms per m3 must stay constant. At 1 atmosphere, the number of atoms/m3 in air at room temperature is about 109, one billion atoms.There is 2 m^3 of some gas with density 0.9 kg/m^3 The volume of gas was increased by factor of 2, What is the density now? Calculate answer to two decimals.Direction: Write the correct answer on the blanks. Inside the box are the possible answers. pwater = 1.0 g/cm3 pethanol=0.76 g/cm3 pmercury=13.6 g/cm3 pair = 1.20 kg/m3 PHe=0.18 kg/m3 Volume of a block: V=lwh Density: p=m/V Volume of a sphere: V-(4/3)Trr Weight: Fg-mg Net force: EF = ma %3D 1. If a block of aluminum measures 4.0 cm x 5.0 cm x 2.0 cm is completely submerged in a tank of water, what volume of water does it displace? 2. What is the mass of the displaced water? 3. What is the weight of the displaced water? 4. How large of a buoyant force acts on the block? 5. The mass of the aluminum block is 108 g. Determine its density.
- Question 4 : A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.3 cm/min. At what rate is the volume of the snowball decreasing when the radius is 11 cm. (Note the answer is a positive number).The density of the atmosphere varies drastically with height, but you can use an average density from sea floor to the space in order to calculate its height. If we approximate this average density to be = 1 Kg/m³, what would be height of the atmosphere? HINT: Since the atmosphere is a fluid (in gas form), you can use the hydrostatic pressure formula (P pgh), just solve for h and use P = 1 atm. BTW, this is how the edge of space is defined, if you make it pass the height of the atmosphere you have reached space :)The basic function of an automobile's carburetor is to atomize the gasoline and mix it with air to promote rapid combustion. Assume that 40 cm? of gasoline is atomized into N spherical droplets. Each droplet has a radius of 2.0 x 10-5 m. Find the total surface area of these N spherical droplets.
- In the text, it was shown that N / V = 2.68×1025 m−3 for gas at STP. (a) Show that this quantity is equivalent to N / V = 2.68×1019 cm−3 , as stated. (b) About how many atoms are there in one μm3 (a cubic micrometer) at STP?(c) What does your answer to part (b) imply about the separation of atoms and molecules?Some farts stink. This is mostly due to the presence of small quantities of hydrogen sulfide gas and mercaptans. The diffusion coefficient of H2S gas in air is 0.2x10 -m²/s. Imagine that you fart 1 meter away from a classmate. How long might you expect it would take for your classmate to smell this unwelcome olfactory intrusion if diffusion were to be the main means of gas dispersal? t= S Does your experience with intestinal gas jibe with this value? What are a couple of good reasons why not? [Lesson: if you fart in a crowd, your best bet is to stay veeeerrrrrryyyyy still!]A submarine dives down to a depth 80 metres beneath the surface of the ocean. Calculate the pressure in atmospheres at that depth, assuming the density of water is 1029 kg/m3, and the air pressure at the surface is 105.2 kPa. Give your answer with two digits of precision. Note: 1 standard atmosphere is 101325 Pa. Your Answer: Answer