Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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The normal stress of a soil sample is165 kPa at void ratio of 0.66. If the compression index of the soil is 0.25, determine the normal stress on the soil at void ratio of 0.56
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- A tri-axial compression test on a cohesive sample of cylindrical in shape, which fails along a plane making an angle of 60 degrees with the horizontal, yields the following effective stress. Compute the angle of internal friction. Compute the cohesion of the soil sample. Compute the shear stress (MN/m^2) at the rupture plane.arrow_forwardThe following results were obtained from an oedometer test on a specimen of saturated clay: 54 107 214 429 214 107 54 27 Pressure (kPa): 1.024 1.012 1.001 0.994 1.068 1.144 1.217 1.243 Void ratio: A layer of this clay 8 m thick lies below a 4 m depth of sand, the water table being at the surface. The saturated unit weight for both soils =19 kN/m3=19 kN/m3. A 4 m depth of fill, unit weight =21 kN/m3=21 kN/m3, is placed on the sand over an extensive area. Determine the final settlement due to consolidation of the clay. If the fill were to be removed some time after the completion of consolidation, what heave would eventually take place due to swelling of the clay?arrow_forward#3arrow_forward
- Problem 1: A cohesive soil sample has an angle of internal friction equal to 30° and a cohesion of 28 kPa. If the maximum shearing stress of the soil is equal to 60 kPa a) What is the confining pressure in the cell for a failure to occur? b) Solve for the maximum principal stress to cause failure. c) Determine the normal stress at the point of maximum shear.arrow_forwardA sample of moist sand taken from the field was found to have a moisture content of 14% and a porosity of 38%. In the laboratory test that simulates field conditions, it was found that at its densest state, its void ratio is 85% and at its loosest state its void ratio is 40%. Determine the void ratio. Select one: a. 0.79 b. 0.57 c. 0.61 d. 0.42arrow_forwardQuestion attachedarrow_forward
- A saturated clay sample in an oedometer is under vertical pressure of 120 kPa and is at a normally consolidated state. The void ratio and the sample height at this stage are 1.21 and 18.40 mm respectively. When the vertical stress was increased to 240 kPa at the end of the consolidation, the thickness of the sample was reduced to 16.80 mm. When the vertical pressure was reduced to the original value of 120 kPa, the sample heaved to a thickness of 16.95 mm. Estimate both the compression index and recompression index of the clay. What would be the reduction in thickness from now if the vertical pressure was increased by 200 kPa? What is the average coefficient volume compressibility during this pressure increment?arrow_forwardDuring an oedometer test on a specimen of saturated clay, the thickness of the specimen decreased from 19.931 mm to 19.720 mm under an increment of stress from 200 to 400 kPa which was maintained for 24 hours. The stress was then removed from the specimen, its thickness was measured as 19.842 mm, and its water content determined as 26.8%. Taking Gs of the particles to be 2.70, calculate the void ratio before and after the application of the stress increment, and the coefficient of volume decrease (m,) for this stress range. (Ans: e,= 0.731, ez= 0.713, m, = 0.052 m²/MN)arrow_forwardA soil specimen has an angle of shearing resistance of 28° and cohesion of 31kPa. The shearing stress on the failure plane is 65kPa. Which of the following most nearly gives the maximum normal stress to cause failure?arrow_forward
- If an unconfined compression test is performed on the same clayey soil as described in Problem 4 , what axial load can be expected at failure? problem 4: A cohesive soil sample is subjected to an unconfined compression test. The sample fails at a pressure of 3850 lb/ft2 [i.e., unconfined compressive strength lb/ft2]. Determine the soil’s cohesion.arrow_forwardx in red is equal to 39arrow_forwardThe size of a sand specimen in a direct shear test was 50 mm x 50 mm x 30 mm (height). It is known that, for the sand, tan phi prime = 0.65/e (where e = void ratio) and the specific gravity of soil solids Gs = 2.65. During the test, a normal stress of 140 kN/m^2 was applied. Failure occured at a shear stress of 105 kN/m^2. What was the mass of the sand specimen?arrow_forward
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