MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- 1st option - answer the height column answer 1 to 10arrow_forwardHow to do and I do not know how to doarrow_forwardPage 2 of 5 B. Organizing and Working with Data. 1. Find the z-score for the weight of a 155-pound woman. The mean weight of woman age 20 or older is 170.6 pounds with a standard deviation of 5.4 pounds. Round your answer to two decimal places.arrow_forward
- The ratings of applicants for credit are normally distributed with a mean of 200 and a standard deviation of 50. Find the 60th. percentile, the rating score that separates the lower 60% from the top 40%. Round to the nearest integer. a. 208 b. 187 c. 211 d. 213arrow_forwardDetermine the number of standard deviations from the mean (z-score). In the United States, the distribution of a male's height has a mean of 69 inches with a standard deviation of 3 inches. How many standard deviations from the mean is John Doe, who is 67 inches tall? Question 15 options: 0.67 standard deviations below the mean 0.33 standard deviations below the mean 2 standard deviations below the mean 1 standard deviation below the meanarrow_forwardPlease do only sub-part "d" for Q6 and also do only sub-part "d" for Q9. Don't use excel formula to solve the question.arrow_forward
- Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). E Click the icon to view the data. In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 H,: Ha #0 O B. Ho: Ha #0 H1: Hd =0 O C. Ho: Ha #0 O D. Ho: Ha = 0 H1: Hd 0arrow_forwardAssume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is between -2.05 and 3.87 and draw a sketch of the region. Sketch the region. Choose the correct graph below. OA. OB. OC. OD. -2.05 3.87 2.05 3.87 -2.05 3.87 -2.05 3.87 The probability is (Round to four decimal places as needed.)arrow_forwardI need help answering parts 4 and 5arrow_forward
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