The necessary value for z Sample 1 Sample 2 n₁ = 400 n₂ = 300 P1 = 0.56 P₂ = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. lower bound = P₁ P2-²a/2V P₂(1-P₂) 7₂ upper bound was determined to be 1.645. Recall the given information. a/2 = 0.56 0.41 0.0559 = = 0.56 0.41 02441 P₁(1-P₁) n1 + Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₂(1-P₂) P₁-P₂ + ²a/2√ P₁(1-P₁) + n₁ 7₂ X 1.645, 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 + 0.56(10.56) 0.41(10.41) 400 300 +
The necessary value for z Sample 1 Sample 2 n₁ = 400 n₂ = 300 P1 = 0.56 P₂ = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. lower bound = P₁ P2-²a/2V P₂(1-P₂) 7₂ upper bound was determined to be 1.645. Recall the given information. a/2 = 0.56 0.41 0.0559 = = 0.56 0.41 02441 P₁(1-P₁) n1 + Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₂(1-P₂) P₁-P₂ + ²a/2√ P₁(1-P₁) + n₁ 7₂ X 1.645, 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 + 0.56(10.56) 0.41(10.41) 400 300 +
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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