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The necessary value for z Sample 1 Sample 2 n₁ = 400 n₂ = 300 P1 = 0.56 P₂ = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. lower bound = P₁ P2-²a/2V P₂(1-P₂) 7₂ upper bound was determined to be 1.645. Recall the given information. a/2 = 0.56 0.41 0.0559 = = 0.56 0.41 02441 P₁(1-P₁) n1 + Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₂(1-P₂) P₁-P₂ + ²a/2√ P₁(1-P₁) + n₁ 7₂ X 1.645, 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 + 0.56(10.56) 0.41(10.41) 400 300 +

The necessary value for z Sample 1 Sample 2 n₁ = 400 n₂ = 300 P1 = 0.56 P₂ = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. lower bound = P₁ P2-²a/2V P₂(1-P₂) 7₂ upper bound was determined to be 1.645. Recall the given information. a/2 = 0.56 0.41 0.0559 = = 0.56 0.41 02441 P₁(1-P₁) n1 + Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₂(1-P₂) P₁-P₂ + ²a/2√ P₁(1-P₁) + n₁ 7₂ X 1.645, 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 + 0.56(10.56) 0.41(10.41) 400 300 +

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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upper bound = P₁ P₂ +Z = 0.56 0.41 02441 a/2 P₁(1-P₁) P₂(1-P₂) 01 7₂ + Submit Skin (you cannot como bal +1.645, 0.56(1-0.56) 400 + Ing the result to four decimal places. X Therefore, a 90% confidence interval for the difference in the population proportions (rounding to four decimal places) is from a lower bound of 0.0559 X to an upper bound of 0.2441 0.41(10.41) 300
Transcribed Image Text:upper bound = P₁ P₂ +Z = 0.56 0.41 02441 a/2 P₁(1-P₁) P₂(1-P₂) 01 7₂ + Submit Skin (you cannot como bal +1.645, 0.56(1-0.56) 400 + Ing the result to four decimal places. X Therefore, a 90% confidence interval for the difference in the population proportions (rounding to four decimal places) is from a lower bound of 0.0559 X to an upper bound of 0.2441 0.41(10.41) 300
Step 3 The necessary value for Za/2 was determined to be 1.645. Recall the given information. Sample 1 n1 = 400 P1 = 0.56 P2 = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. P₁(1-P₁) P₂(1-P₂) 1 72 lower bound = P₁-P₂-²a/2 = 0.560.41 Sample 2 n2 = 300 = 0.0559 = 0.56 0.41 = 02441 X Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₁(1-P₁) P₂(1-P₂) upper bound = P₁ P₂ + ²a/2√ n1 n2 X + ✔ - 1.645, + 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 0.56(1 0.56) + 400 + 0.41(1 0.41) 300
Transcribed Image Text:Step 3 The necessary value for Za/2 was determined to be 1.645. Recall the given information. Sample 1 n1 = 400 P1 = 0.56 P2 = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. P₁(1-P₁) P₂(1-P₂) 1 72 lower bound = P₁-P₂-²a/2 = 0.560.41 Sample 2 n2 = 300 = 0.0559 = 0.56 0.41 = 02441 X Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₁(1-P₁) P₂(1-P₂) upper bound = P₁ P₂ + ²a/2√ n1 n2 X + ✔ - 1.645, + 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 0.56(1 0.56) + 400 + 0.41(1 0.41) 300
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