The NBA wants to determine how many of its players would be in favor of shortening the length of the regular season. They send out a survey to 72 players and find that 54 (75%) are in favor of reducing the length of the season. Assume all assumptions are met, we now want to create a 90% Confidence Interval for the proportion of players in favor of reducing the length of the season.   (0.746, 0.754) (0.705, 0.795) (0.666, 0.834) (0.714, 0.786) (0.622, 0.878)

1. Out of a sample of 150 people who walked into a fast-food restaurant, 135 said they prefer ketchup to mustard on their hamburgers. With 89% confidence, what is the confidence interval for the population mean of customers that prefer ketchup to mustard on their hamburgers? O CI = (86.09%, 93.91%) O CI = (85.20%, 94.80%) O CI = (82.61%, 95.87%) O CI = (83.69%, 96.31)   2. Out of all the students that attend Yale University, 1,982 were selected to participate in a school survey about their commute to school. 70% said that their commute to school was fine, while the others were dissatisfied with their commute. Calculate a 90% confidence interval for the proportion of students at Yale who feel their commute to school is fine the way it is. O CI = (68.76%, 71.98%) O CI = (67.35%, 72.65%) O CI = (68.31%, 71.69%) O CI = (67.98%, 72.02%)   3. Out of a sample of 500 people, 25% exercise daily. What is the confidence interval for the…

Suppose you want to estimate the proportion of employed adults who would continue working if they won $10 million in the lottery. A previous study on the issue of how to sample proportion of 0.59. How many employed adults should be randomly sampled in order to get a 99% confidence interval with a width of 0.3?

Come up with  your own data for a problem that would ask for a 90% confidence interval utilizing Z. Clearly label your variables.