The motor delivers 65 hp to the A36 steel shaft while it rotates at 1500 RPM.  The shaft is supported on smooth bearings at B and E, which allow free rotation of the shaft.  The gears C and D fixed to the shaft remove 70% and 30% of the power delivered by the motor, respectively.  Determine the diameter of the shaft to the nearest 1/8 in. if the allowable shear stress is ττallow = 12 ksi and the allowable angle of twist of D with respect to A is 0.25 degrees.

The customised shaft has a diameter of 50 mm. A square parallel key is suggested to be used for mounting a gear into this shaft. The shaft is to be made of SAE 1095 Carbon Steel with a yield stress of 572 MPa. The gear is made from SAE 1045 Carbon Steel with a yield stress of 531 MPa. A key can be made of SAE 1018 Carbon Steel with a yield stress of 372 MPa or SAE 316 Stainless Steel of 241 MPa. The gear transmits torque of 2,000 +P N-m and has a hub length of 100 mm. The design factor is chosen as 3.0 and the width of the key is 12.7 mm. Specify the keys using two materials and explain which material should be recommended in such a design scenario. Key Figure 1: Key, Gear and Shaft You may use the following equations: == T D/2(WL) 4T σ DLH 2T L = TDW 4T L= σDH

The motor at A delivers 50 hp to the shaft while rotating 25 hp at 1800 rev/min. Each gear removes the power shown in the figure. If the shaft is made of a steel that has an allow- able shear stress of 9 ksi, determine the required diameters, B 15 hp dAB 10 hp dAB, dBc, and dcD, to the nearest 1/s in. d BC dcD E

Q:  Part A: Determine the absolute maximum shear stress in the shaft. Part B: Determine the angle of twist of end EE of the shaft relative to BB. Given: The turbine develops 150 kW of power, which is transmitted to the gears such that CC receives 70% and DD receives 30%. The rotation of the 100-mm diameter A-36 steel shaft is ωomega = 600 rev/min . The journal bearing at EE allows the shaft to turn freely about its axis. The shear modulus of elasticity for A-36 steel is 75 GPa.