The most commonly found phenotype in the natural population of a species is called the?

In a population of 500 fruit flies, 250 are genotype RR, 100 are genotype Rr and 150 are genotype rr. Determine the allele frequencies for this gene in this population. Remember that the frequencies should add to 1. Please show your work.

Give typing answer with explanation and conclusion In a village in Quebec the frequency of a common mutant cystic fibrosis allele (CFcf) is approximately 0.025. What is the risk of a gamete carrying the mutant allele in this area?

In this version of the simulation (500 population size; 500 carrying capacity), all fish are equally likely (though not 100% likely) to survive and reproduce. There are no mutations, nor are there any entering or leaving the population. When they reproduce, they choose a mate from the pool at random and produce ten offspring by chance with the probability of the offspring’s genotypes determined by the punnett square. What caused the allele frequencies to change and vary in the trials? (ex attached).

House mouse (Mus musculus) Gene of interest: B4galnt2 (encodes glycosyltransferase enzyme) • Allele R: Associated with prolonged bleeding due to issues with blood clotting; associated with resistance to bacterial infections due to absence of intestinal expression. Allele C: Associated with increased susceptibility to bacterial infections; not associated with prolonged bleeding. A B C The population is closed; there are no new mice coming in. The cages are setup to allow for random mating. The B4galnt2 gene is not associated with any mating preferences or non-random mating patterns. Studies have shown that mutations in this locus are extremely rare. The population is EXTREMELY large. The population is kept in well maintained environment, free of bacterial infections. The mouse food is supplemented with a low dose of blood coagulator, which helps the blood clot and eliminates any prolonged bleeding. None of the genotypes display any side effects to this medication. The population is…

Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…