the moon is 3.84 x10^8 meters on the average from earth. It takes the moon 27.32 days to complete orbit the earth. what is the orbital radius of a satellite that takes 8 hour to complete orbit the earth?

A pilot with a mass of 70.55 kg is flying a small plane in a circular path with a radius of 100.0 m. If a centripetal force of 635N is needed to maintain the pilot’s circular motion, what is the plane and pilot's speed?

A geosynchronous orbit is one in which the satellite stays in the same relative position above the earth, as the earth rotates. To do so, the satellite needs to have an orbital period of 1 day. Given that the moon has an orbital period of 27.3 days and a semi-major axis of 384,000 km, determine the radius of a geosynchronous orbit using Kepler's 3rd law. Enter your answer in km.

A centripetal force of 175 N acts on a 1,450-kg satellite moving with a speed of 5,100 m/s in a circular orbit around a planet. What is the radius of its orbit?   I got 2.155*10^9  however 2,155,00,000 is the wrong answer

A satellite orbits the Earth at a radius of 2.2×10 7 m. What is its orbital period?

A satellite of mass 2,134 kg orbits the Earth at an altitude of 3,434 km in a circular orbit. How many hours does it take for this satellite to complete one full revolution? Mass of the Earth:  kg. Mean radius of the Earth: 6370 km.

The tidal acceleration due to the moon at the surface of the earth is approximately 2.44*10^-5 m/s^2. If the moon was closer to the earth by a factor of 0.9. What then would the tidal acceleration be?

Titania completes one (circular) orbit of Uranus in 8.71 days. The distance from Uranus to Titania is 4.36×108m. What is the centripetal acceleration of Titania?

A centripetal force of 200 N acts on a 1,000-kg satellite moving with a speed of 5,000 m/s in a circular orbit around a planet. What is the radius of its orbit?

A satellite is orbiting earth  at a distance of  3.1 X 105 m above the surface of the Earth. What is its orbital speed? (G = 6.67 X 10-11 Nm2/Kg2; M of Earth = 5.97 x 10 24 kg; Radius of Earth = 6.37 x 10 6 m)