The moment of force P about point A shown * in the figure is equal to .............. P=5N O 10 O 0 05
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- The block of weight W is pulled by the force P inclined at the angle to the horizontal. Find the smallest force P and the corresponding angle that would cause impending sliding of the block. The angle of static friction between the block and the ground is s.The figure shows a steel bar being processed by a rolling mill. Given that P=80kN and r =0.016, determine the force F required to advance the bar at a constant speed.Two equivalent system of forces and moments act on the plate are shown in the figure below. Determine the force P. * 60 N 20 N 60 N 1.5m 1,5m 200 Nm 1.5m E M. 60 N E 4m 4m 100 N System 1 System 2
- The figure shows the routes through which a material point can reach point 2 from point A or B, starting from point 1. The force field acting on the material point is given as F = -2xi - 3y2j° (N). According to this: a. Determine whether the force field is conservative or not. b. Compare the work done by the applied force by calculating for both routes. c. Repeat the requirements of (a) and (b) for the force field F = -yi – xj* (N).4 A ski resort chair lift has towers spaced 38 m horizontaly appart. The upper tower is 15 m higher than the previous tower. If the chairs are 12 m horizontally appart and the first chair is 5 m past the lower tower what is the tension on both ends of the cable? 1:37:01 Book The mass of each chair is 350 Kg and the height above the lower tower for each chair's attachment to the cable is 0.58537 m, 4 m, 9.4244 m. Lower Tower Cable Tension = Upper Tower Cable Tension = kN. KN.Two bodies is connected in point C, are supported by rigid underlay at an angle α. F is the force acting on right body. We are considering the weight of bodies G and the friction between the bodies and the underlay. Length of bodies l=2000mm. G1= 160 N, G2= 180 N, α = 30° Find: 1.) Find the magnitude of the force so that it slips on the underlay 2.) Draw the dependence of the force F as a function of the coefficient of friction f (in the range 0-0.5)
- An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F1=200 lbf, F2=250 lbf, and F3=100 Ibf with 0 = 30 degrees and p=44 degrees. If the eye bolt is in equilibrium, what is the y-component of the sum of other forces on the bolt (force from the nut and plate on the bolt) ? If you add up %3D the three force vectors, the sum other force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The y-direction is positive going up. For example, if you find the sum of forces 1, 2, and 3 are 100 Ibf going up, then the other forces in the y-direction must be pointing to the down (-100 lbf) to put the eye bolt in equilibrium. Eye bolt steel plate Nut & Washer esc DOO D00 F4 F3 AA %24 F10Find the sum of the horizontal forces in Newton if F1 = 100 N at 30 deg N of E and F2 = 80 N at 45 deg N of W.3-In the scheme below, 4 objects are hanging from each of the rings and 5 ropes (blue) keep the entire scheme in balance. The known values are m1=30 kgm1=30 kgα=60ºα=60ºβ=30ºβ=30ºγ=70º a) Attach the force diagram on each of the rings with the graphical decomposition of the forces that are not exclusively on the Cartesian axes. b) Determine the tractions T1, T2, T3, T4 and T5. c) Determine the mass of weights 2, 3, 4 and 5. Tip: If you feel comfortable, use software to solve the systems of equations.
- The structure consists of a spring CD and a solid member ABC with a slot at B. The peg at B fits loosely into the slot at B and can hence be interpreted as a smooth support. The unstretched length of the spring is 80 mm. 50 mm 150 mm 50 mm A D C B k = 600 N/m 1.1 Draw separate free-body diagrams of member ABC and the spring CD. 1.2 Comment on the existence of two-force members and three-force members in this system. 1.3 Determine the reactions at A and B on the member ABCA 10m light rod AB is horizontally placed. One end of this rod is pin supported at point A, and the other end B is connected with a rope BD, which is inclined 30° with respect to x axis. A 10kg box hangs at point C of this rod. Which of the following solutions for the tension force in rope BD is CORRECT? (g=9.8m/s²) O O O A TBD = 117.6 N TBD = 196 N TBD = 169.7 N Don't Know TBD = 98.0 N 6m ► 4m 10kg B D 30°A FBD should include the isolated system and only the known forcesand moments. false O true