The maximum speed of the bob of a simple pendulum is vmax = 1.8 m/s. At the position where the potential energy is double the kinetic energy (U= 2K), the speed of the bob is: v = 1.16 m/s Ov= 1.04 m/s O v= 1.27 m/s Ov=1.38 m/s

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Chapter1: Units, Trigonometry. And Vectors
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The maximum speed of the bob of a simple pendulum is vmax = 1.8 m/s. At the
position where the potential energy is double the kinetic energy (U= 2K), the speed
of the bob is:
O v= 1.16 m/s
O v= 1.04 m/s
O v = 1.27 m/s
O v = 1.38 m/s
The wave function for a wave on a taut string is given by: y(x,t) = 0.08 sin(0.5mxx-
in meters and it is in seconds. The transverse
Transcribed Image Text:The maximum speed of the bob of a simple pendulum is vmax = 1.8 m/s. At the position where the potential energy is double the kinetic energy (U= 2K), the speed of the bob is: O v= 1.16 m/s O v= 1.04 m/s O v = 1.27 m/s O v = 1.38 m/s The wave function for a wave on a taut string is given by: y(x,t) = 0.08 sin(0.5mxx- in meters and it is in seconds. The transverse
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