The mass moment of inertia I of a disk is given by 1=1m²², where m is the mass of the disk and r is the radius. Consider a steel disk with a density of 7,800 kg and a thickness of 1 cm. When r = 10 cm, what is the volume (in m³) of the steel disk? When r = 10 cm, what is the mass (in kg) of the steel disk? kg When r = 10 cm, what is the mass moment of inertia (in kg - m²)? kg-m² Similarly, obtain the rest of the volumes (in m³), mass (in kg), and I (in kg. m²) values to fill in the blanks in the table below. r (m) volume (m³) 0.10 0.11 0.12 0.13 mass (kg) I= 1 = mr² (kg - m²) .

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Create a graph that shows I as a function of r for the steel disk. (Select the correct graph.)
I (kg.m²)
I (kg-m²)
O
0.6
0.5
0.4
0.3
0.2
0.1
0.15
0.2
0.25
r (m)
no
0.6
0.5
0.4
0.3
0.2
0.1
0.15
0.2
0.25
r (m)
1 (kg-m²)
0.6
0.5
0.4
0.3
0.2
0.1
0.15
0.2
r (m)
0.25
1 (kg-m²)
0.6
0.5
0.4
E
0.3
0.2
0.1
0.15
0.2
0.25
r (m)
Transcribed Image Text:Create a graph that shows I as a function of r for the steel disk. (Select the correct graph.) I (kg.m²) I (kg-m²) O 0.6 0.5 0.4 0.3 0.2 0.1 0.15 0.2 0.25 r (m) no 0.6 0.5 0.4 0.3 0.2 0.1 0.15 0.2 0.25 r (m) 1 (kg-m²) 0.6 0.5 0.4 0.3 0.2 0.1 0.15 0.2 r (m) 0.25 1 (kg-m²) 0.6 0.5 0.4 E 0.3 0.2 0.1 0.15 0.2 0.25 r (m)
The mass moment of inertia I of a disk is given by
I
1=21mr²,
where m is the mass of the disk and r is the radius. Consider a steel disk with a density of 7,800 kg and a thickness of 1 cm.
When r = 10 cm, what is the volume (in m³) of the steel disk?
m³
When r = 10 cm, what is the mass (in kg) of the steel disk?
kg
When r = 10 cm, what is the mass moment of inertia (in kg. m²)?
kg-m²
Similarly, obtain the rest of the volumes (in m³), mass (in kg), and I (in kg. m²) values to fill in the blanks in the table below.
I=//mr²
(kg-m²)
r (m)
0.10
0.11
0.12
0.13
0.14
0.15
0.16
0.17
0.18
0.19
0.20
0.21
0.22
0.23
0.24
0.25
volume (m³) mass (kg)
100
Transcribed Image Text:The mass moment of inertia I of a disk is given by I 1=21mr², where m is the mass of the disk and r is the radius. Consider a steel disk with a density of 7,800 kg and a thickness of 1 cm. When r = 10 cm, what is the volume (in m³) of the steel disk? m³ When r = 10 cm, what is the mass (in kg) of the steel disk? kg When r = 10 cm, what is the mass moment of inertia (in kg. m²)? kg-m² Similarly, obtain the rest of the volumes (in m³), mass (in kg), and I (in kg. m²) values to fill in the blanks in the table below. I=//mr² (kg-m²) r (m) 0.10 0.11 0.12 0.13 0.14 0.15 0.16 0.17 0.18 0.19 0.20 0.21 0.22 0.23 0.24 0.25 volume (m³) mass (kg) 100
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